3 years ago

20. Lee uses Bill Payer from his bank account to pay his internet bill. Lee pays the same amount each month.

1 answer:

3 0

It's the same amount each month, for a year. So:
total money ÷ times money was taken out= how much has been taken out.

$600÷12=50

You might be interested in

Using the Distributive Property to factorize the equation 3x^2 + 24x = 0, you get _____The solution of the equation is _____

stiv31 [10]

Solution is x=0 x=-8

7 0

3 years ago

|x + 1| + 4 ≤ 2

irga5000 [103]

Answer:

no solution

Step-by-step explanation:

8 0

3 years ago

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 108.7-cm and a standard dev

Luden [163]

Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)

To get the probability of less than 109.1 cm, the solution is computed by:

z (109.1) = (X-mean)/standard dev

= 109.1 – 108/ 0.6

= 1.1/0.6

=1.83333, look this up in the z table.

P(x < 109.1) = P(z < 1.8333) = 0.97 or 97%

3 0

3 years ago

Find the product 7 x 300 = hundreds

Evgesh-ka [11]

7 x 300 = 2,100 hope i helped and there are 21 hundreds in 2,100

4 0

3 years ago

Read 2 more answers

Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen

harina [27]

The matrix

$A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}$

has eigenvalues $\lambda$ such that

$\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0$

$(\cos\theta-\lambda)^2+\sin^2\theta=0$

$(\cos\theta-\lambda)^2=-\sin^2\theta$

$\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}$

$\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}$

$\sin^2\theta\ge0$ for all values of $\theta$ , so we need to have $\sin\theta=0$ in order for $\lambda$ to be real-valued. This happens for

$\sin\theta=0\implies\theta=n\pi$

where $n$ is any integer, and over the given interval we have $\theta=0$ and $\theta=\pi$ .

4 0

3 years ago