The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
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Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
m=#miles
so 130= .5m+30
subtract 30 from each side
100$= .5m than divide .5 to isolate m
m= 200
Step-by-step explanation:
First, convert the kilograms to grams. One kilogram is 1000 grams. So multiply it by 1000. Then subtract 2305 from 4000. 4000-2305=1695. So 1695 grams were taken out.
15÷8=1.875
I would round up to $1.88 /cookie.
