= > x² + 7x + 12 = 12
= > x² + ( 4 + 3 )x + 12 = 12
= > x² + 4x + 3x + 12 = 12
= > x( x + 4 ) + 3( x + 4 ) = 12
= > ( x + 4 ) ( x + 3 ) = 12
Percy did correct till this step. But by doing like this, Percy can't get the values of the variable x.
Percy should follow the following steps :
= > x² + 7x + 12 = 12
Add -12 on both sides,
= > x² + 7x + 12 - 12 = 12 - 12
= > x² + 7x = 0
= > x( x + 7 ) = 0
= > ( x = 0 ) or ( x + 7 = 0 )
= > ( x = 0 ) or ( x = - 7 )
Hence, required value(s) of x is 0 or -7
Answer:
(-5,0) or (0,-25) is another solution
Step-by-step explanation:
Do you have a list of choices? If not, you could choose random choices for x and y to determine if they are solutions. Start by letting y = 0. We see that x = -5, so (-5, 0) is a solution to this equation. In fact, it represents the x-intercept of this line. Now, let x = 0. We now see that y = -25, so (0, -25) is another solution to the equation of this line. This coordinate pair is the y-intercept of the line. Try using other values of x and y to see if you can come up with other solutions to this equation.
Answer:
f=1
Step-by-step explanation:
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