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densk [106]
3 years ago
10

Which of the following transformations will produce a figure that is similar, but not congruent, to the original figure?

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer: The answer is A. dilation :)

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OT bisects ∠DOG. Find the measure of ∠DOG if ∠DOT = 4x + 4 and ∠TOG = 5x – 3
g100num [7]

Answer:

\huge\boxed{64^o}

Step-by-step explanation:

If OT is bisects ∠DOG, then m∠DOT = m∠TOG. Therefore

4x+4=5x-3    |<em>subtract 4 from both sides</em>

<em />4x+4-4=5x-3-4\\\\4x=5x-7<em>|subtract 5x from both sides</em>

<em />4x-5x=5x-5x-7\\\\-x=-7<em>|change the signs</em>

<em />x=7<em />

Calculate the measure of ∠DOG

m∠DOG = 2(m∠DOT)

m\angle DOG=2(4\cdot7+4)=2(28+4)=2(32)=64

6 0
3 years ago
Find the surface area of the figure shown,<br> correct to 2 decimal places.
agasfer [191]

Answer:

230.73m^2

Step-by-step explanation:

A=2a^2+4ah=2*4^2+4*4*4=96m^2 (square prism)

A=2\pi rh+2\pi r^2=2*\pi *4*9+2*\pi *4^2 = 326.73m^(cylinder)

326.73-96=230.73m^2 (\frac{3}{4} cylinder)

7 0
3 years ago
What does the graph of lnx look like?
qwelly [4]
This is what the graph of in(x) looks like

7 0
3 years ago
Q7. What would be the best next step in solving the following equation for x?<br><br> 8x - 4 = 10
bagirrra123 [75]

Answer:

The next step would be adding -4 to the other side since it would cancel out -4

Step-by-step explanation:

8 0
3 years ago
On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapid
Elza [17]

Answer:

L(t)=7600e^{0.2273t}

Step-by-step explanation:

-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:

P=P_oe^{rt}

Where:

  • P is the population after t days.
  • P_o is the initial population given as 7600
  • r is the rate of growth
  • t is time in days

-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5

-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.

Hence, the exponential growth function will be expressed as:

P=P_oe^{rt},\ \ \ P=L(t)\\\\\therefore L(t)=7600e^{5\frac{t}{22}}\\\\=7600e^{0.2273t}

7 0
3 years ago
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