Answer:
= 0.714 (in decimal fraction)
The probability that the death in 2014 was not caused by heart diseases or Unintentional Injuries = 0.714
= 0.714
Step-by-step explanation:
Let's interpret the question our way ti solve it .
Total deaths in 2014:
2626418
Death caused by Heart Diseases:
614348
Death caused by Unintentional Injuries:
750401
Therefore, we can deduced that, the number of death not caused by Heart Diseases or Unintentional Injuries = Total deaths in 2014 minus sum of the recorded death.
= 2626418 - ( 614348 + 136053)
= 2626418 - 750401
= 1876017.
Now, the probability that there were death in 2014 is 1 (one)
To find the probability that death we're not caused by heart diseases or Unintentional Injuries:
= 1 - Pr (Death Caused by heart diseases) + Pr (Death causes by Unintentional Injuries)
= 1 - (0.234 + 0.052)
= 1 - 0.286
= 0.714
To Check:
= 1876017 / 2626418
Divide to the lowest term
=0.714
Answer:
Graph (C)
Step-by-step explanation:
To find whether the graph\table represents a relationship or a function we have to analyze the input-output values given.
Graph A.
In this graph for every input value (x-value) there are two output values (y-values).
For x = -2, y = -2, 2
So the graph doesn't represent a function.
Graph B.
For every x value there are two y-values
For x = -5, y = -3, 3
So the graph doesn't represent a function.
Graph C.
For every input value there is a different y-value.
Therefore, graph represents a function.
Graph D.
In this graph for x = 3, y = 1, 2, 3, 4
For one value of x, there are four values of y.
Therefore, graph doesn't show the relationship.
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer:
there were no inequalities to choose from but I believe the answer is y ≤ 4x
Step-by-step explanation:
