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viva [34]
3 years ago
10

Each week, you drive 150 miles. Your car gets 25 miles to the gallon, and gas prices are $3 per gallon. How much gas money will

you spend on gas each week?
Mathematics
2 answers:
geniusboy [140]3 years ago
8 0
So if the car gets 25 miles a gallon and you travel 150 miles a week all you would have to do is divide 150 by 25 and the multiply that number by 3 which is $18
Marat540 [252]3 years ago
6 0

           (150 miles/week) x (1 gallon / 25 miles) x (3 $/gallon)

       =    (150 x 1 x 3) / (25)   (miles-gallon-$ / week-miles-gallon)

       =                      18            $/week .
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Need answer ASAP <br> *MARKING BRAINLIEST
Rzqust [24]

Answer:

y=-2/3x +1

Slope = The change in y over the change in x so to do this you can use the two points To find the change in y to be -1-3=4 And the change in x to be 3 -(-3)=6 so you get -4/6 which can be simplified to -2/3 Then to find the next part find the y intercept which is y=1 at x=0

8 0
3 years ago
Determine all the unknown values of the figure below.
Vanyuwa [196]

Answer:

F=10, S=26

Step-by-step explanation:

We know that the base is 24. Using that information, 10^2+24^2=26^2 which is a pythagorean triple

3 0
3 years ago
Sam kept track of the number of problems he was assigned for his math homework on the box plot.
yulyashka [42]

Answer:

Statement A is correct about Sam's box and whisker plot.

Step-by-step explanation:

We have been given a box plot and we are asked to find out true statement according to the box plot.

Since we know data represented by box plot is divided in four equal parts.

Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.

Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.

IQR=Q_3-Q_1

Upon substituting given values from box plot we get,

IQR=19-11=8

From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.


4 0
3 years ago
Read 2 more answers
What is 2. 3/6 +1/6 +1 2/3
Kaylis [27]
3/6+1/6+1 2/3
Make 1 2/3 into an improper fraction:
5/3
Give them all common denominators by multiplying both sides of 5/3 by 2:
10/6
Then the question becomes:
3/6+1/6+10/6
Now you add the numerators and the denominator stays the same:
14/6
Now you can simplify by dividing both sides by 2:
7/3
Now you can make it a mixed number:
2 1/3

Hope this helps :)
8 0
3 years ago
Read 2 more answers
A craftsman can sell 10 jewelry sets for $500 each. He knows
liraira [26]

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning=\text{Price of each set}\times \text{no of set}

Earning =(500-25n)(10+n)

E=5000+500n-25n^2-250n

differentiate to get the maximum value

\frac{dE}{dn}=-50n+250

Equate \frac{dE}{dn} to get maximum value

-50n+250=0

n=\frac{250}{50}

n=5

Thus must sell 5 extra set to maximize its earnings.

5 0
3 years ago
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