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Lesechka [4]
3 years ago
11

PLEASE HELP QUICKLY I WILL MARK BRAINLIEST AND IF YOU ARE TRYING TO GET FREE POINT I WILL REPORT YOU

Mathematics
2 answers:
Ganezh [65]3 years ago
8 0
The meaning of a quadrilateral inscribed in a circle is that the angles on the opposite vertices are supplementary or in other words equals to 180 degrees.

On this exercise is asked you to find the measure in degrees of angle A. First of all, you have to find the value of x. To do this you have to select two angles on this case angles B and D.

m<B+m<D=180       Substitute the values of angles B and D
       148+x=180        Subtract 148 in both sides to isolate x
               x=32

Now that the value of x is known, you can substitute it into the expression representing angle A.

m<A=2x+1
m<A=2(32)+1
m<A=65

The measure of angle A is 65 degrees.

Juliette [100K]3 years ago
5 0
<B+<D = 180
x+148 = 180
x = 32

<A = 2(32) + 1
<A = 64+1
<A = 65
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If n is a positive even number, then the product of (-12)ⁿ will be what
kipiarov [429]

Answer:

a positive even number.

Step-by-step explanation:

I suggest plugging in random positive even numbers and finding a pattern. (-12)^2 = 144. (-12)^ 4= 20,736. this is because two negatives, when multiplied, turn to a positive. the n is how many times negative 12 is multiplied with itself

3 0
3 years ago
86° 34° Х X = ____ degrees help quick pls​
Rufina [12.5K]

Answer:

60 degrees

Step-by-step explanation:

The angles all have to add up to 180, so you can do

34 + 86 +x = 180\\120 + x = 180\\x = 60

3 0
3 years ago
Read 2 more answers
Passing through (-2,-6) and parallel to the line whose equation is y=-3x+4
Licemer1 [7]

Answer:

y = -3x - 12

Step-by-step explanation:

Lines that are parallel have the same gradient.

Therefore using the point (-2,-6) you can make your own equation.

-6 will be y, -2 will be x

All you have to do is find the y-intercept which is C in <em>y</em><em>=</em><em>mx</em><em>+</em><em>c</em>

-6 = -3(-2) + c

-6 = 6 + c

-12 = c

Therefore;

<u>y = -3x - 12</u>

6 0
2 years ago
What is the 20th term of the sequence that begins -5,15,-45, 135. ?
larisa [96]
The 20th term in the sequence should be 5811307335.
Hope I didn't mess up for your sake
6 0
3 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

----------

Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
2 years ago
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