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Ksju [112]
3 years ago
13

HELP ASAP PLEASE!!!

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Whatever answer you think it should be, the answer must exclude 0.

1/x = 1/0 which is undefined.

D is the only possible answer. None of the others make that exclusion. There is one other thing to consider: do any of the others exclude 0.

More importantly, what have you been told about the  natural numbers. Some people include 0 in what the natural numbers are. Does your teacher or your instructions?

The whole numbers include 0. Without the restriction (3) is not the answer.

If it does, then that is not an answer. I think that D is the safest answer.


ValentinkaMS [17]3 years ago
4 0
4. All real numbers except x = 0. Correct me if I’m wrong please
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AleksAgata [21]
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system

Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
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The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
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3 years ago
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Step by step...shows how to get -22/7

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3 years ago
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

4 0
3 years ago
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Answer:

  • <u><em>Option B. There will be close to 40 TVs but probably not exactly 40 TVs not showing a sports channel.</em></u>

Explanation:

There are a total of <em>7 sports channels</em> and 4 non-sports channels o<em>ut of 11 channels.</em>

The probability that one <em>TV will be not be showing a sports channel</em>, P(not S), is:

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  • P(not S) = 4/11.

The <em>best prediction</em> on <em>how many TVs will not be showing a sports channel </em>is, the expected value, which is equal to the number of TVs mulitplied by P(not S):

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Since this is a random variable, the expected value is not the exact number of TV but just a probability.

Hence, the answer is the option <em>B: There will be close to 40 TVs but probably not exactly 40 TVs not showing a sports channel.</em>

3 0
3 years ago
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