The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
Step by step...shows how to get -22/7
There are 23 nickles in her purse
Answer:
Therefore, the inverse of given matrix is

Step-by-step explanation:
The inverse of a square matrix
is
such that
where I is the identity matrix.
Consider, ![A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%263%5C%5C3%266%5Cend%7Barray%7D%5Cright%5D)








Therefore, the inverse of given matrix is

Answer:
- <u><em>Option B. There will be close to 40 TVs but probably not exactly 40 TVs not showing a sports channel.</em></u>
Explanation:
There are a total of <em>7 sports channels</em> and 4 non-sports channels o<em>ut of 11 channels.</em>
The probability that one <em>TV will be not be showing a sports channel</em>, P(not S), is:
- P(not S) = number of non-sports channels / number of channels.
The <em>best prediction</em> on <em>how many TVs will not be showing a sports channel </em>is, the expected value, which is equal to the number of TVs mulitplied by P(not S):
- P(not S) = 110 × 4/11 = 40.
Since this is a random variable, the expected value is not the exact number of TV but just a probability.
Hence, the answer is the option <em>B: There will be close to 40 TVs but probably not exactly 40 TVs not showing a sports channel.</em>