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3 years ago

How do u solve 6 1/2 - 1 9/10

2 answers:

5 0

Just convert the fractions into decimals. for example, 6 1/2 equals 6.5 as a decimal. 1 9/10 would be converted to 1.9. Then just do 6.5-1.9, and that equals 4.6.

Semmy [17]3 years ago

3 0

6 1/2 - 1 9/10
=6 5/10 - 1 9/10
=4 6/10
=4 3/5

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14. Find the distance between (7,217pi/180 ) and (5,-23pi/36 ) on the polar plane.

irina [24]

Answer: the distance is 3.49 units

Step-by-step explanation:

There are some ways to find the exact distance, i will calculate the distance in rectangular coordinates.

When we have a point (R, θ) in polar coordinates, we can transform it into rectangular coordinates as:

x = R*cos(θ)

y = R*sin(θ)

Then we have:

(7,217pi/180 )

R = 7

θ = (217/180)*pi

x = 7*cos( (217/180)*pi) = -5.59

y = 7*sin( (217/180)*pi) = -4.21

So this point is (-5.59, -4.21) in rectangular coordinates.

And the other point is (5,-23pi/36 )

R = 5

θ = -(23/36)*pi

x = 5*cos( -(23/36)*pi ) = -2.11

y = 5*sin( -(23/36)*pi ) = -4.53

So this point is (-2.11, - 4.53)

Then the point distance between those points is:

D = I (-2.11, -4.53) - (-5.59, -4.21) I

D = I (-2.11 + 5.59, -4.53 + 4.21) I

D = I (3.48, -0.32) I = √( (3.48)^2 + (-0.32)^2) = 3.49

4 0

3 years ago

NEED HELP ASAP PLEASE IM TRYNA PASS

V125BC [204]

Answer:

segment SV

Step-by-step explanation:

Observing the figure

we know that

The side that is common to triangle SUV and triangle VTS is only the segment SV

There are no common angles to triangle SUV and triangle VTS

therefore

The answer is the segment SV

3 0

3 years ago

If x>2, then x^2-a-6 / x^2-4=

nadezda [96]

We know that x > 2 ( or : x ≠ +/- 2 )
We have to factorize the numerator and the denominator:
x² - x - 6 = x² - 3 x + 2 x - 6 = x ( x - 3 ) + 2 ( x - 3 ) = ( x - 3 ) ( x + 2 )
x ² - 4 = ( x - 2 ) ( x + 2 )
$\frac{(x-3)(x+2)}{(x-2)(x+2)}= \frac{x-3}{x-2}$

7 0

3 years ago

The three steps are shown below were used to find an expression equivalent to 2/5( 15x- 30y)+10x

Tresset [83]

step 1 is to distribute the bracket by $\frac{2}{5}$