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3 years ago

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Find a number such that 12% if the number is 60

1 answer:

Lelechka [254]3 years ago

5 0

Use a proportion to answer the question

60 = 100%
x = 12

12 x 60 = 720
720 / 100 = 7.2

7.2 is 12% of 60, which is your answer<span />

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Is -9.7 rational or irrational give reasoning

asambeis [7]

A rational number is any number that can be expressed as a ratio of two integers (hence the name "rational"). For example, 1.5 is rational since it can be written as 3/2, 6/4, 9/6 or another fraction or two integers. Pi (π) is irrational since it cannot be written as a fraction.

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3 years ago

- f(x) = x^5 – 8x^3 – 9x (find all zeros/roots)

grigory [225]

$x^5-8x^3-9x\\\\[Factor]x(x+3)(x-3)(x^2+1)\\\\[Set all the items equal to 0.]x = 0\\\\x+3=0\\x=-3\\\\x-3=0\\x=3\\\\x^2 +1=0\\x^2=-1\\x=i,-i$

The 5 roots are 0, -3, 3, i, and -i.

⭐ Answered by Hyperrspace (Ace) ⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

3 0

3 years ago

aleksley [76]

First multiply (-5/6) and (1/6) to get
$- \frac{5}{36}$
then you subtract that from (8/9) to get
$\frac{27}{36}$
final answer is
$\frac{3}{4}$

5 0

3 years ago

Use the diagram to answer the following

Vedmedyk [2.9K]

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8 0

2 years ago

Read 2 more answers

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago