All categories

4 years ago

Someone give me the answer

Mathematics

1 answer:

Mademuasel [1]4 years ago

5 0

We want to begin with nine, which gives us as follows:

Then, we want to subtract:

9 -

And we are subtracting x:

9 - x

The expression is 9 - x for the steps in the image given.

Hope this helps!! :)

You might be interested in

The headless horseman rode 4/1-2 miles from the old Dutch burying ground to the haunted woods he then traveled 9/3-4 miles from

enyata [817]

Answer:

26 1/4 miles

Step-by-step explanation:

9+4+12=25

1/2+3/4=1 1/4

25+1 1/4= 26 1/4

7 0

3 years ago

Select the correct answer. What are the intercepts of y = 4x − 2?

ValentinkaMS [17]

x-intercept(s): (1/2, 0) or (0.5, 0)

y-intercept(s): (0, −2)

8 0

3 years ago

Read 2 more answers

Cosθ=−2√3 , where π≤θ≤3π2 .

Alex787 [66]

Answer:

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we know that

Applying the trigonometric identity

$sin^2(\theta)+ cos^2(\theta)=1$

we have

$cos(\theta)=-\frac{\sqrt{2}}{3}$

substitute

$sin^2(\theta)+ (-\frac{\sqrt{2}}{3})^2=1$

$sin^2(\theta)+ \frac{2}{9}=1$

$sin^2(\theta)=1- \frac{2}{9}$

$sin^2(\theta)= \frac{7}{9}$

$sin(\theta)=\pm\frac{\sqrt{7}}{3}$

Remember that

π≤θ≤3π/2

Angle θ belong to the III Quadrant

That means ----> The sin(θ) is negative

$sin(\theta)=-\frac{\sqrt{7}}{3}$

step 2

Find the sec(β)

Applying the trigonometric identity

$tan^2(\beta)+1= sec^2(\beta)$

we have

$tan(\beta)=\frac{4}{3}$

substitute

$(\frac{4}{3})^2+1= sec^2(\beta)$

$\frac{16}{9}+1= sec^2(\beta)$

$sec^2(\beta)=\frac{25}{9}$

$sec(\beta)=\pm\frac{5}{3}$

we know

0≤β≤π/2 ----> II Quadrant

sec(β), sin(β) and cos(β) are positive

$sec(\beta)=\frac{5}{3}$

Remember that

$sec(\beta)=\frac{1}{cos(\beta)}$

therefore

$cos(\beta)=\frac{3}{5}$

step 3

Find the sin(β)

we know that

$tan(\beta)=\frac{sin(\beta)}{cos(\beta)}$

we have

$tan(\beta)=\frac{4}{3}$

$cos(\beta)=\frac{3}{5}$

substitute

$(4/3)=\frac{sin(\beta)}{(3/5)}$

therefore

$sin(\beta)=\frac{4}{5}$

step 4

Find sin(θ+β)

we know that

$sin(A + B) = sin A cos B + cos A sin B$

In this problem

$sin(\theta + \beta) = sin(\theta)cos(\beta)+ cos(\theta)sin (\beta)$

we have

$sin(\theta)=-\frac{\sqrt{7}}{3}$

$cos(\theta)=-\frac{\sqrt{2}}{3}$

$sin(\beta)=\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute the given values in the formula

$sin(\theta + \beta) = (-\frac{\sqrt{7}}{3})(\frac{3}{5})+ (-\frac{\sqrt{2}}{3})(\frac{4}{5})$

$sin(\theta + \beta) = (-3\frac{\sqrt{7}}{15})+ (-4\frac{\sqrt{2}}{15})$

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

8 0

4 years ago

Simplify negative 2 and 1 over 9 – negative 4 and 1 over 3

iren2701 [21]

Ok to start you have to put

2+-1/9 - 4+-1/3

what exactly is the question because without the proper info. nobody is going to be able to figure it out.

5 0

3 years ago

Read 2 more answers

5 (x+9) = 3 (x +8) + 2x

zmey [24]

Answer:

No solution

Step-by-step explanation:

Distribute

5x+45 = 3x+24+ 2x

Combine terms

45=5x-5x

45=0

This statement is not true so it is no solution

8 0

3 years ago