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2 years ago

Rationalize the denominator: √2

Mathematics

2 answers:

Aleks04 [339]2 years ago

7 0

here is your right answer..

bixtya [17]2 years ago

6 0

here is your answer hope it's helpful for you thankyou

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How I can answer this question, NO LINKS, If you answer correctly I will give u brainliest!

Vikentia [17]

Answer:

$\huge\boxed{\sf n = 7}$

Step-by-step explanation:

Given equation is:

$(7^2)^4=n^8$

Multiply 2 to 4

$7^8=n^8$

While comparing both sides, we get:

7 = n

n = 7

$\rule[225]{225}{2}$

Hope this helped!

7 0

2 years ago

Read 2 more answers

I need a help please Answer for me all the question

irina1246 [14]

Answer:

see below

Step-by-step explanation:

The sum of the interior angles is 180

<1 + <2 + <4 = 180

<1 + 31+ <4 = 180

<1 + <4 = 180-31

<1 + <4 = 149

<2 + <3 = 180 because it forms a straight line

31 + <3 = 180

<3 = 180-31

<3 = 149

Setting theses equal (since they are both equal to 149)

<1 + <4 = <3

The exterior angle is equal to the sum of the opposite interior angles

4 0

2 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

How to graph y=-4|x+2|-5

Elina [12.6K]

$y= -4|x+2| -5 \\ \\x= -6 \Rightarrow y=-4|-6+2|- 5= -4|-4|- 5= -4*4 -5 =\\ \\=-16-5=-21\\ \\ \\x= -4\Rightarrow y=-4|-4+2|- 5= -4|-2|- 5= -4*2 -5 =\\ \\ =-8-5=-13\\ \\ \\x= -2 \Rightarrow y=-4|-2+2|- 5= -4|0|- 5= -4*0 -5 =-5\\ \\ \\x= 0 \Rightarrow y=-4|0+2|- 5= -4|2|- 5= -4*2 -5 =-8-5=-13\\ \\ \\x= 2 \Rightarrow y=-4|2+2|- 5= -4| 4|- 5= -4*4 -5 =-16-5=-21$

4 0

2 years ago

Area of plane and composite figures

Phoenix [80]

Dont click the link they track your ips

6 0

2 years ago