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Maru [420]
3 years ago
13

Rationalize the denominator: √2

Mathematics
2 answers:
Aleks04 [339]3 years ago
7 0

<u>here</u><u> </u><u>is</u><u> </u><u>your</u><u> </u><u>right</u><u> </u><u>answer</u><u>.</u><u>.</u>

bixtya [17]3 years ago
6 0

<u>here</u><u> </u><u>is</u><u> </u><u>your</u><u> </u><u>answer</u><u> </u><u>hope</u><u> </u><u>it's</u><u> </u><u>helpful</u><u> </u><u>for</u><u> </u><u>you</u><u> </u><u>thankyou</u><u> </u>

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100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
Which expression is equivalent to 6423?
Ronch [10]
Please show all of the expressions.
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