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3 years ago

Which equation(s) model inverse variation? Select all that apply.

1 answer:

7 0

For this case, what you should know is that the equations that represent an inverse variation are those that could not form a straight line, for example.

We have then:

Equation 1:

pv = 13

Rewriting:

p = 13 / v

P and v are represent an inverse variation.

Equation 2:

z = (2 / x)

z and x are represent an inverse variation.

Answer:

equations represented inverse variation are:

pv = 13

z = (2 / x)

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A rectangular bird sanctuary is being created with one side along a straight riverbank. The remaining three sides are to be encl

shusha [124]

Answer:

For a rectangle of length L and width W, the perimeter is:

P = 2*L + 2*W

And the area is:

A = L*W.

Now, we know that the sanctuary has one side along a straight riverbank, then we will not fence that side. if L > W, then makes sense to put one of the "length" sides in the riverbank, in that way, we are saving more fence for the other 3 sides.

Then we will have that, the total length of fence used is:

12km = 2*W + L (two times the width and only one time the length are fenced).

From this, we can isolate one of the variables:

L = 12km - 2*W

And replace that in the area equation:

A(W) = (12km - 2*W)*W = 12km*W - 2*W^2.

To maximize this function, we must see when the first derivate is equal to zero:

A'(W) = 12km - 4*W = 0

12km = 4*W

12km/4 = 3km = W

Then the width that maximizes the area is W = 3km.

And the maximum area will be:

A'(3km) = 12km*3km - 2*(3km)^2 = 18km^2

And the length can be computed with the equation:

L = 12km - 2*W = 12km - 2*3km = 6km

6 0

3 years ago

Bradley is returning home from a place that is 2 kilometers away. The function y = 2,000 − 90x represents Bradley's distance fro

GenaCL600 [577]

Answer:

The function is a linear function.
The function changes at a constant rate.

Step-by-step explanation:

The degree of x is 1, so the function is a linear function.

The coefficient of x is -90, a constant rate of change that is negative, so the function is <em>decreasing</em>.

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3 years ago

The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alik

tankabanditka [31]

Answer:

a. difference of means

Step-by-step explanation:

Given that :

Mean , x = 9.4

Standard deviation, $s.d_1$ = 2.5

Number, $n_1$ = 12

Mean, y = 6.5

standard deviation, $s.d_2$ = 2.4

Number, $n_2$ = 12

The null hypothesis is : $H_0: \mu_1=\mu_2$

The alternate hypothesis is : $H_1: \mu_1>\mu_2$

Level of significance, $\alpha$ = 0.1

From the $\text{standard normal table, right tailed,}$ $t_{1/2}$ = 1.363

Since out test is right tailed.

Reject $H_0$ , if $T_0>1.363$

We use the test statics,

$t_0=\frac{(x-y)}{\sqrt{\frac{s.d_1}{n_1}+\frac{s.d_2}{n_2}}}$

$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$

$t_0=2.899$

$|t_0|=2.899$

$\text{Critical value}$

The value of $|t_{1/2}|$ with minimum $\left(n_1-1,n_2-1)$ that is 11 df is 1.363

We go $|t_0|=2.899$ and $|t_{1/2}|$ = 1.363

Decision making:

Since the value of $|t_0|>|t_{1/2}|$$ and we reject the $H_0$

The p-value : right tail $H_a:(p>2.8988)$

= 0.00724

Therefore the value of $p_{0.1} > 0.00724$ , and so we reject the $H_0$

Thus we are testing 'the difference of means" in this problem.

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3 years ago

The population of a species of rabbit triples every year. This can be modeled by f(x) = 4(3)x and f(5) = 972. What does the 3 re

Liula [17]

The 3 represents how many times the species multiplies.

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tresset_1 [31]

It depends on how much the questions were worth

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