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Delvig [45]
3 years ago
15

We have 9 balls, numbered 1 through 9, and 27 bins. How many different ways are there to distribute these 9 balls among the 27 b

ins? Assume the bins are distinguishable (e.g., numbered 1 through 27).
Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

7625597484987 ways

Step-by-step explanation:

Given the following :

Number of ball(k) = 9

Number of bins (n) = 27

How many different ways are there to distribute these 9 balls among the 27 bins.

Here, the balls have different labels (1 to 9)

The bins are also distinguishable, therefore each ball can go into any of the 27 distinct bins.

Therefore, the different ways are there to distribute these 9 balls among the 27 bins equals = n^k

27^9 = 7625597484987 ways.

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What fraction of 3 2/5 is 9 7/8
yanalaym [24]

Answer:

  395/136

Step-by-step explanation:

(9 7/8)/(3 2/5) = (79/8)/(17/5) = (79/8)(5/17) = 395/136

Since 9 7/8 is larger than 3 2/5, it is an improper fraction.

5 0
4 years ago
Write the ratio<br> 2/3 /5<br> in simplest form
Ierofanga [76]

Answer:

A) 2/15

Step-by-step explanation:

So just divide it normally, do keep change flip

2/3*1/5

2/3 keep

divison change

Denomeinator, flip it, 5 to 1/5

now multiply

2/15

5 0
3 years ago
Use multiples to write two fractions equivalent to 7/9.
Nitella [24]

Answer:

\frac{14}{18} , \frac{21}{27}

Step-by-step explanation:

To create equivalent fractions multiply the numerator and denominator of the fraction by the same multiples.

Using a multiple of 2, then

\frac{7}{9} = \frac{7(2)}{9(2)} = \frac{14}{18}

Using a multiple of 3, then

\frac{7}{9} = \frac{7(3)}{9(3)} = \frac{21}{27}


4 0
4 years ago
2* <br> 7-t<br> 8*y<br> 9=9<br> Which is the equation?
GaryK [48]

Answer:

2+7_t×y+9 je pense que c la reponses

6 0
4 years ago
A cone-shaped hole is drilled into a solid cube of metal as shown. If the cube has sides of length 9 cm, what is the volume of t
ziro4ka [17]
V (cube)=9³=729 cm³
V (cone)=1/3*π*R²*H= 1/3*π*3²*9=84.8 cm³
V (metal)= 729-84.8=644.2 cm³
7 0
3 years ago
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