The probability according to the given scenario is:
(a) <em>0.0395</em>
(b) <em>0.95</em>
(c) <em>0.076</em>
The given values are:
(a)
The probability that the b/w has tuberculosis as well as having (+) test will be:
→ 
By substituting the values, we get
→ 
→ 
(b)
The probability that a person does not have tuberculosis will be:
→ 
→ 
→ 
(c)
The person does not have tuberculosis as well as have a (+) test, the probability will be:
→ 
→ 
→ 
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Answer:8.55
Step-by-step explanation:
3 and 2 are the ansewers i tink

(a) For dx/dt=6, dy/dt = 2·6 = 12
(b) For dy/dt=2, 2 = 2·dx/dt ⇒ dx/dt = 1
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The value of x is irrelevant for this question.
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If your function is 2^x +1 or 2^(x +1), it needs to be written as such. The answer above applies to the function given.