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Artist 52 [7]
3 years ago
12

n Monday 2⁄3 of the team practiced, Tuesday 7⁄8 , Wednesday 1⁄2 , and Thursday 3⁄4 . On which day were the most team members pre

sent at practice? A. Wednesday B. Tuesday C. Thursday D. Monday
Mathematics
2 answers:
Ratling [72]3 years ago
6 0

Answer:

Tuesday

Step-by-step explanation:

You have to compare 2/3, 7/8, 1/2 and 3/4. An easy way to do this is by converting fractions into decimal expressions, as follows:

2/3 = 0.67

7/8 = 0.875

1/2 = 0.5

3/4 = 0.75

Therefore, 7/8 is bigger than 2/3, 1/2 and 3/4

Tanya [424]3 years ago
4 0
Answer is Tuesday because if you turn all the fractions into a percentage then Tuesday has the highest percentage.
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A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why
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Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

Area=length\times width square units

Let x be the length and y be the width.

Since the area is 0.24 square meter, we have the equation:

Area=x\times y = 0.24, with x and y measures in meters

If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.

Now choosing some values for "x", we have:

Put x = 1

1\times y = 0.24

∴ y = 0.24

Now put x = 0.5 we get

0.5\times y = 0.24

∴ y = 0.48

Put  x = 0.25

0.25\times y = 0.24

∴ y = 0.96

Put x = 2

2\times y = 0.24

∴ y = 0.12

8 0
3 years ago
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Which equation represents a population of 210 animals that decreases at an annual rate of 14%
soldi70 [24.7K]

Answer:

The equation i.e. used to denote the population after x years is:

P(x) = 490(1 + 0.200 to the power of x

Step-by-step explanation:

This problem could be modeled with the help of a exponential function.

The exponential function is given by:

P(x) = ab to the power of x

where a is the initial value.

and b=1+r where r is the rate of increase or decrease.

Here the initial population of the animals are given by: 490

i.e. a=490

Also, the rate of increase is: 20%

i.e. r=20%

i.e. r=0.20

Hence, the population function i.e. the population of the animals after x years is:

P(x) = 490(1 + 0.200 to the power of x

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Answer:

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Step-by-step explanation:

1716/16=107

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Step-by-step explanation:

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12

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