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Lilit [14]
3 years ago
11

Prove that 3^17−3^15+3^13 is divisible by 73.

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

3^13*73

Step-by-step explanation:

3^17-3^15+3^13 So you factor out 3^13

=3^13(3^4-3^2+1)

3^4-3^2+1=73

3^13*73

Is this RSM?

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Step-by-step explanation:

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Kai has a mass of 55kg. What would Kai weigh on Mars? (The gravitational field strength on Mars is 3.7N/kg). Give your answer to
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Answer:

203.5 N

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4 years ago
One leg of a right triangle is 1 cm less than the hypotenuse, and the other leg is 8 cm less than the hypotenuse. What is the le
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Answer:

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Step-by-step explanation:

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5 0
4 years ago
Trig Help please! 50 points!
IgorLugansk [536]

Answer:

C

Step-by-step explanation:

Remember the mnemonic: SohCahToa, where:

\sin(\theta)=\text{opposite}/\text{hypotenuse}\\\cos(\theta)=\text{adjacent}/\text{hypotenuse}\\\tan(\theta)=\text{opposite}/\text{adjacent}

Let's determine our side lengths first.

Note that our angle is A. So, we have to determine the sides with respect to A.

The opposite side to A is 16.

The adjacent side is 12.

And the hypotenuse is 20.

With this, we can find our trig ratios:

Sine:

\sin(A)=\text{opp}/\text{hyp}

Substitute 16 for the opposite and 20 for the hypotenuse. This yields:

\sin(A)=16/20

Reduce:

\sin(A)=4/5

Cosine:

\cos(A)=\text{adj}/\text{hyp}

Substitute 12 for the adjacent and 20 for the hypotenuse. This yields:

\cos(A)=12/20

Reduce:

\cos(A)=3/5

Tangent:

\tan(A)=\text{opp}/\text{adj}

Substitute 16 for the opposite and 12 for the adjacent. This yields:

\tan(A)=16/12

Reduce:

\tan(A)=4/3

So, our answers are:

\frac{4}{5}, \frac{3}{5}, \text{ and } \frac{4}{3}

Out of the answer choices, the choice that represents this is C.

So, our correct answer is C.

And we're done!

4 0
3 years ago
Read 2 more answers
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