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BARSIC [14]
3 years ago
9

Can Someone give me a 5 paragraph essay about all of the uses in Microsoft Word.

Computers and Technology
1 answer:
ElenaW [278]3 years ago
4 0
No one is going to write an essay for you, but I can give 3 uses, if you're writing in this format (intro, body1, body2, body3, conclusion)


1. Using it in the business world (Resume)
2. Using it for school (reports, essays)
3. Using it for organization (notes, checklists)


You might be interested in
Write a program whose input is two integers, and whose output is the first integer and subsequent increments of 5 as long as the
Anna11 [10]

Answer:

The program in Python is as follows:

num1 = int(input())

num2 = int(input())

if num2 < num1:

   print("Second integer can't be less than the first.")

else:

   for i in range(num1,num2+1,5):

       print(i,end=" ")

Explanation:

This gets the first integer from the user

num1 = int(input())

This gets the second integer from the user

num2 = int(input())

If the second is less than the first, the following prompt is printed

<em>if num2 < num1:</em>

<em>    print("Second integer can't be less than the first.")</em>

If otherwise, the number between the intervals is printed with an increment of 5

<em>else:</em>

<em>    for i in range(num1,num2+1,5):</em>

<em>        print(i,end=" ")</em>

<em />

6 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
3 years ago
Write a Java program to create a class called Cars. The class should include three instance variables: makes (type: String), mod
Fiesta28 [93]

Answer:

Explanation:

This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.

import java.util.Scanner;

class TestCars{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Car Make: ");

       String make1 = in.next();

       System.out.print("Enter Car Model: ");

       String model1 = in.next();

       System.out.print("Enter Car Year: ");

       int year1 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make2 = in.next();

       System.out.print("Enter Car Model: ");

       String model2 = in.next();

       System.out.print("Enter Car Year: ");

       int year2 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make3 = in.next();

       System.out.print("Enter Car Model: ");

       String model3 = in.next();

       System.out.print("Enter Car Year: ");

       int year3 = in.nextInt();

       Cars car1 = new Cars(make1, model1, year1);

       Cars car2 = new Cars(make2, model2, year2);

       Cars car3 = new Cars(make3, model3, year3);

       car1.show();

       car2.show();

       car3.show();

   }

}

class Cars {

   String makes, models;

   int years;

   public Cars(String makes, String models, int years) {

       this.makes = makes;

       this.models = models;

       this.years = years;

   }

   public void show() {

       System.out.println("Car's make: " + this.makes);

       System.out.println("Car's model: " + this.models);

       System.out.println("Car's year: " + this.years);

   }

}

5 0
3 years ago
In the case below, the original source material is given along with a sample of student work. Determine the type of plagiarism
Katyanochek1 [597]

Answer:

B. Paraphrasing plagiarism

Explanation:

<em> Paraphrasing plagiarism:</em>

This is when the sentences or words of the original source of information is being rephrased or stated in your own words.

The type of plagiarism in the student work is a paraphrasing plagiarism because the information in the original source was rephrased by the student using his own sentences and words to express the information in the original material. Also the referenced author was  acknowledge without acknowledging the original author of the material.

8 0
3 years ago
1. Explain the distinction between interpretation and compilation. What are the comparative advantages and disadvantages of the
serious [3.7K]

Answer:

11: Compiler translates a high level source program into a target equivalent (machine language).

An interpreter implements a virtual machine, the high-level programming language of which is the "machine language." The interpreter reads statements more or less one at a time in that language, and executes them as they go along.

12: One could also consider Java either. A compiler (complicated translator) can create code, which is then executed by a complicated virtual machine (interpreter)

13: A preprocessor is an initial translator which removes comments and white space, and group characters together into tokens such as keywords, identifiers, numbers, and symbols, as well as simple syntactic structure analyses. A compiler uses in-depth analysis and nontrivial transformation.

14: C++ implementations based on the early AT&T compiler created an intermediate program in C rather than assembly language

15: Stack-based language, similar to modern Java compiler byte code

16: A method in which a simple interpreter implementation evolves into building more complex versions until the compiler is built.

17: A compiler which translates byte code into machine language immediately prior to each program execution.

18: Lisp and Prolog

19: TEX and TROFF are one of such compilers that translate high-level document descriptions into laser printer or phototypesetter commands. Query language processors for database systems are also compilers that translate languages such as SQL into primitive file operations.

21: without havin to call multiple tools with command-line tools, You can write an entire program in an IDE.

8 0
3 years ago
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