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liraira [26]
3 years ago
8

Before creating a brief to design a product, what is needed

Computers and Technology
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

A good design brief often begins with some information about the client and what their brand stands for. Including this helps to connect an individual project with the bigger picture. Aim to capture key points about what the company does, how big they are, and what their key products or services are.

Explanation:

A good design brief often begins with some information about the client and what their brand stands for. Including this helps to connect an individual project with the bigger picture. Aim to capture key points about what the company does, how big they are, and what their key products or services are.

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Define a function compute_gas_volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use
jeyben [28]

Question:

Define a function compute_gas_volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use the gas equation PV = nRT, where P is pressure in Pascals, V is volume in cubic meters, n is number of moles, R is the gas constant 8.3144621 ( J / (mol*K)), and T is temperature in Kelvin.

Answer:

This solution is implemented in C++

double compute_gas_volume(double P, double T, double n){

   double V = 8.3144621 * n * T/P;

   return V;

}

Explanation:

This line defines the function, along with three parameters

double compute_gas_volume(double P, double T, double n){

This calculates the volume

   double V = 8.3144621 * n * T/P;

This returns the calculated volume

   return V;

}

To call the function  from the main, use:

<em>cout<<compute_gas_volume(P,T,n);</em>

<em />

<em>Where P, T and n are double variables and they must have been initialized</em>

5 0
3 years ago
There will be 10 numbers stored contiguously in the computer at location x 7000 . Write a complete LC-3 program, starting at loc
Artist 52 [7]

Answer:

The LC-3 (Little Computer 3) is an ISA definition for a 16-bit computer. Its architecture includes physical memory mapped I/O via a keyboard and display; TRAPs to the operating system for handling service calls; conditional branches on N, Z, and P condition codes; a subroutine call/return mechanism; a minimal set of operation instructions (ADD, AND, and NOT); and various addressing modes for loads and stores (direct, indirect, Base+offset, PC-relative, and an immediate mode for loading effective addresses). Programs written in LC-3 assembler execute out of a 65536 word memory space. All references to memory, from loading instructions to loading and storing register values, pass through the get Mem Adr() function. The hardware/software function of Project 5 is to translate virtual addresses to physical addresses in a restricted memory space. The following is the default, pass-through, MMU code for all memory references by the LC-3 simulator.

unsigned short int get Mem Adr(int va, int rwFlg)

{

unsigned short int pa;

// Warning: Use of system calls that can cause context switches may result in address translation failure

// You should only need to use gittid() once which has already been called for you below. No other syscalls

// are necessary.

TCB* tcb = get TCB();

int task RPT = tcb [gettid()].RPT;

pa = va;

// turn off virtual addressing for system RAM

if (va < 0x3000) return &memory[va];

return &memory[pa];

} // end get MemAdr

Simple OS, Tasks, and the LC-3 Simulator

We introduce into our simple-os a new task that is an lc3 Task. An lc3 Task is a running LC-3 simulator that executes an LC-3 program loaded into the LC-3 memory. The memory for the LC-3 simulator, however, is a single global array. This single global array for memory means that alllc3 Tasks created by the shell use the same memory for their programs. As all LC-3 programs start at address 0x3000 in LC-3, each task overwrites another tasks LC-3 program when the scheduler swaps task. The LC-3 simulator (lc3 Task) invokes the SWAP command every several LC-3 instruction cycles. This swap invocation means the scheduler is going to be swapping LC-3 tasks before the tasks actually complete execution so over writing another LC-3 task's memory in the LC-3 simulator is not a good thing.

You are going to implement virtual memory for the LC-3 simulator so up to 32 LC-3 tasks can be active in the LC-3 simulator memory without corrupting each others data. To implement the virtual memory, we have routed all accesses to LC-3 memory through a get Mem Adr function that is the MMU for the LC-3 simulator. In essence, we now have a single LC-3 simulator with a single unified global memory array yet we provide multi-tasking in the simulator for up to 32 LC-3 programs running in their own private address space using virtual memory.

We are implementing a two level page table for the virtual memory in this programming task. A two level table relies on referring to two page tables both indexed by separate page numbers to complete an address translation from a virtual to a physical address. The first table is referred to as the root page table or RPT for short. The root page table is a fixed static table that always resides in memory. There is exactly one RPT per LC-3 task. Always.

The memory layout for the LC=3 simulator including the system (kernel) area that is always resident and non-paged (i.e., no virtual address translation).

The two figures try to illustrate the situation. The lower figure below demonstrates the use of the two level page table. The RPT resident in non-virtual memory is first referenced to get the address of the second level user page table or (UPT) for short. The right figure in purple and green illustrates the memory layout more precisely. Anything below the address 0x3000 is considered non-virtual. The address space is not paged. The memory in the region 0x2400 through 0x3000 is reserved for the RPTs for up to thirty-two LC-3 tasks. These tables are again always present in memory and are not paged. Accessing any RPT does not require any type of address translation.

The addresses that reside above 0x3000 require an address translation. The memory area is in the virtual address space of the program. This virtual address space means that a UPT belonging to any given task is accessed using a virtual address. You must use the RPT in the system memory to keep track of the correct physical address for the UPT location. Once you have the physical address of the UPT you can complete the address translation by finding the data frame and combining it with the page offset to arrive at your final absolute physical address.

A Two-level page table for virtual memory management.

x7000 123F x7000 0042

x7001 6534 x7001 6534

x7002 300F x7002 300F

x7003 4005 after the program is run, memory x7003 4005

x7004 3F19

7 0
3 years ago
Read 2 more answers
What has global css rulesets of an angular 8 project mcq.
love history [14]

In order to conserve the angular momentum, Angular speed (w) often increases. The 'none of the above' option has global CSS rulesets of an angular 8 project mcq.

  • The angular momentum of a rigid object is known as the product of the moment of inertia and the angular velocity.

Angular speed is described as how quickly an object rotates. it is seen as the change in the angle of the object per unit of time.

See full question below

What has global CSS rulesets of an angular 8 project mcq.

A. e2e

B. None of the above

C. App

D. node_modules

Learn more from

brainly.com/question/24336703

7 0
2 years ago
Given the code as follows: main() { int i = 3, n; float x; x = i; n = 8 % x; } What problem will occur? Group of answer choices
Bess [88]

Answer:

A compilation error will occur.

Explanation:

The % operator does not accept a float as its right-hand operand.

7 0
3 years ago
Consider the function definition void Demo( int&amp; intVal, float floatVal ) { intVal = intVal * 2; floatVal = float(intVal) +
Fynjy0 [20]

Answer:

myInt=40

myFloat=4.8

Explanation:

First look at the function definition .It has two arguments intVal is passed by reference while floatVal is passed by value.So the changes done on the myInt variable will be reflected on the original argument because when a variable is passed by reference the the changes are reflected on the original argument but when a variable is passed by value the function created a duplicate copy of it and work on them so changes are not reflected on the original argument.So myInt will get doubled while myFloat will remain the same.

5 0
3 years ago
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