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3 years ago

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Emil bought a camera for $268.26, including tax. He made a down payment of $12.00 and paid the balance in 6 equal monthly paymen

ts. What was Emil's monthly payment for this camera?

1 answer:

Dennis_Churaev [7]3 years ago

3 0

$111.78 was the monthly payment

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The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

Identify the linear graph.

jenyasd209 [6]

The answer is: The second one. Why?

Because, when it's a linear graph, the slope of the graph cannot change.

And that's the only graph that fits the criteria

Hope this helped! c:

5 0

3 years ago

Read 2 more answers

Using the distributive property to find the product (y — 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y

klio [65]

I got a =16.
Hope this helps! :D

4 0

2 years ago

Read 2 more answers

A woman standing on a hill sees a flagpole that she knows is 65 ft tall. The angle of depression to the bottom of the pole is 14

Oliga [24]

Answer:

Let the distance between woman and pole be "x".

From diagram,

In ΔOAB,

tan 18 = $\frac{Perpendicular}{Base}$

tan 18 = $\frac{65 -y}{x}$

∴ x = $\frac{65 -y}{tan 18}$ ................ (1)

In ΔOBC

tan 14 = $\frac{Perpendicular}{Base}$

tan 14 = $\frac{y}{x}$

y = x × tan 14 ..............(2)

equating (2) in (1), we get;

x = $\frac{65}{tan 18 + tan 14}$

x = $\frac{65}{0.574}$

∵ tan 18 + tan 14 = 0.574

<em>∴ x = 113.2 ft</em>

<em>i.e. The her distance from the pole is 113.2 ft.</em>

3 0

3 years ago

Find the slope from the table using the slope formula

larisa86 [58]

Answer:

it false

Step-by-step explanation:

7 0

3 years ago