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uranmaximum [27]
2 years ago
8

Help me please, will give brainliest

Mathematics
1 answer:
ANTONII [103]2 years ago
6 0

A\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]

B\left[\begin{array}{ccc}3&-5&3\\2&3&1\\4&1&-3\end{array}\right]

Now,\\\\2B-A\\\\2\left[\begin{array}{ccc}3&-5&3\\2&3&1\\4&1&-3\end{array}\right]-\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]\\\\=\left[\begin{array}{ccc}6&-10&6\\4&6&2\\8&2&-6\end{array}\right] -\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]\\\\=\left[\begin{array}{ccc}5&-10&1\\4&11&-5\\8&-1&-2\end{array}\right]

Row 1 column 2(a12)=-10

Hence,-10 is your answer.

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There are 33 of them altogether and pay £311 in total. How many kids are in the family? Adults pay £15 and kids pay £7
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Answer:

Step-by-step explanation

  1. Let x be the number of adults and y the number of kids

We can then write this two equations :

          x+y= 33

          15x+7y= 311

  • let's solve the two eaquations

to do that we should combine them both in a way that help us get rid of one of the variables.

             Let's multiply the first equation by -7 to get rid of y by adding it to thr second equation

             -7x-7y= -231

        now add both equations .

              15x+7y-7x-7y=311-231

    we get :  8x = 80

as you notice y is gone and we get a classic easy equation to solve

                x= 80/8

                   = 10

so the number of adults is 10

let's go back to the first equation ( x+y= 33) and replace x with 10

                10+y= 33

                  y= 33-10

                     =23

let's check using the second equation :

            (10*15)+(23*7) = 311

that is true

so :

  •  the number of adults is 10
  • the number of kids is 23
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Step-by-step explanation:


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Answer:

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Step-by-step explanation:

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