Answer:
a. attached graph; zero real: 2
b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Step-by-step explanation:
p(x) = x³ + 4x² + 6x - 36
a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.
p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0
b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.
2 | 1 4 6 -36
1 6 18 0
x² + 6x + 18 = 0
Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²
√Δ = 6i
x = -6±6i/2 = 2(-3±3i)/2
x' = -3-3i
x" = -3+3i
p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Answer:
no
Step-by-step explanation:
1.8×100 would be 180 because you're moving the decimal place two to the right.
For a better understanding of the solution provided here, please find the diagram attached.
In the diagram, ABCD is the room.
AC is the diagonal whose length is 18.79 inches.
The length of wall AB is 17 inches.
From the given information, we have to determine the length of the BC, which is depicted a 
, because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.
In order to determine the length of the wall BC, or , we will have to employ the Pythagoras' Theorem here. Thus:
Thus, 
inches
and hence, the given room is not a square.
Answer:
y=mx+b
Step-by-step explanation:
