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3 years ago

Please help me with this. If you show your work I will give brainliest if there are 2 answers

Mathematics

1 answer:

AfilCa [17]3 years ago

6 0

<h3>Answer: 22.5</h3>

Work Shown:

450 calories = 20 ounces

450/20 calories = 20/20 ounces ..... divide both sides by 20

22.5 calories = 1 ounce

This smoothie has 22.5 calories per ounce.

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Is sqrt(1 - sin^2 θ) = cos θ true? if so, in which quadrants does angle θ terminate?

jonny [76]

Answer:

I and IV

Step-by-step explanation:

Since 1-sin(θ)² = cos(θ)², the given equation is equivalent to ...

√(cos(θ)²) = |cos(θ)| = cos(θ)

This will be true where the cosine is non-negative, in the first and fourth quadrants.

7 0

3 years ago

I need help with this I don’t understand

klasskru [66]

Answer:

Step-by-step explanation:

∠3 = 180 - ∠1 {linear pair}

= 180 - 105

= 75°

∠2 = ∠3 {Corresponding angles"

∠2 = 75

5 0

2 years ago

To make rice, you mix 1.5 cups of water for every 1 cup of dry rice. This will make 2 servings. How many cups of dry rice and ho

dalvyx [7]

Answer:

7.5 cups of water

5 cups of dry rice

Step-by-step explanation:

In total 1.5 water and 1 cup rice will equal 2 servings. If you are serving 10 people, you need to multiply each by 5.

6 0

3 years ago

Represent, the set of numbers between 5 to 50 when they are divided by 8 then the remainder is 3,It by description method, listi

Debora [2.8K]

By descriptive method = Set A is a set of all natural numbers between 5 and 50 which gives remainder 3 when divided by 8.Listing method : A = { 11, 19, 27, 35, 43} and Set builder method : A = { x : x ∈ N, x = 8 c + 3 and 1 < c < 5

We are given that:

Number range 5 - 50

Remainder = 3 when the number is divided by 8

We need to find the sets of numbers between 5 to 50 when they are divided by 8 gives remainder 3 by description method, listing method and set builder method.

Let the set be A

Descriptive Method

Set A is a set of all natural numbers between 5 and 50 which gives remainder 3 when divided by 8.

Listing Method

A = { 11, 19, 27, 35, 43}

Set Builder Method

A = { x : x ∈ N, x = 8 c + 3 and 1 < c < 5

Therefore, we get that, by descriptive method = Set A is a set of all natural numbers between 5 and 50 which gives remainder 3 when divided by 8.Listing method : A = { 11, 19, 27, 35, 43} and Set builder method : A = { x : x ∈ N, x = 8 c + 3 and 1 < c < 5

#SPJ9

3 0

2 years ago

Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr

mixer [17]

Answer:

A . 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

<u>Oliver's Interviewees</u>

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

$\frac{70}{100} * \frac{176}{1}$

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

$\frac{30}{100} * \frac{176}{1}$

Cross multiply

52.8 were 9th-graders interviewed by Oliver

<u>Jenny's Interviewees</u>

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

$\frac{75}{100} * \frac{140}{1}$

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

$\frac{25}{100} * \frac{140}{1}$

Cross multiply

35 students were 10th-graders interviewed by Jenney.

<u />

<u>Total calculation</u>

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

<h2>Therefore, there are 36 more 10th than 9th.</h2>

<u />

<h3><u>Extra Info:</u></h3>

<u>Oliver's Interviewees Percentage</u>

Since we are given 30% of the 9th-grade class and 70% of the 10th-grade class, first, let's add the percentages. To do so, set it up as a fraction;

30% = $\frac{30}{100}$ while, 70% = $\frac{70}{100}$

Now solve it;

$\frac{30}{100} + \frac{70}{100}$

Simplify; cancel bottom zero's;

$\frac{30}{1} + \frac{70}{1}$

Add the remaining numerators;

30 + 70 = 100

Which is 100%

<u>Jenny's Interviewees Percentage</u>

Since we're given 75% of the 9th-grade class and 25% of the 10th-grade, it will end up the same answer. I'll show you how; first, let's add the percentages. To do so, set it up as a fraction;

25% = $\frac{25}{100}$ and, 75% = $\frac{75}{100}$

Now solve it;

$\frac{25}{100} + \frac{75}{100}$

Simplify; cancel bottom zero's

$\frac{25}{1} + \frac{75}{1}$

Add the remaining numerators;

25 + 75 = 100

Meaning 100%

5 0

3 years ago