In order to compare the amount of wax, you have to calculate the volume of both candles.
Candle of booth A = πr² h/3
A = π * 4² * 6/3
A = π * 16 * 2
A = 32π
Now, Candle of Booth B = π * 5² * 5/3
B = π * 25 * 5/3
B = 41.6π
In short, Booth B sells the candle with more wax.
Hope this helps!
Hey there!
2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.
1.25f + 2.75f = 4f
4f + 2 = 10
Subtract 2 from both sides.
4f = 8
Divide both sides by 4 to solve for f.
f = 2
I hope this helps!
It takes 15 minutes for Ms. Peter to drive from park to her home
Given :
from her home to the park at an average speed of 30 miles per hour and
returned home along the same route at an average speed of 40 miles per hour
it takes 20 minutes to travel
Convert 20 minutes in to hour (divide by 60)
20 minutes = 1/3 hour
We know that distance = speed x time
From home to park, distance =
So , distance between home and park is 10 miles
Now we calculate the time taken to return from park to home

Time taken is 1/4 hours. Convert it into minutes by multiplying by 60

So it takes 15 minutes for Ms. Peter to drive from park to her home
Learn more : brainly.com/question/18839247
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
C=2πr
Hoped i helped BYEEEEEEEEEEEEEEEEEEEEEEEEE