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Anarel [89]

2 years ago

ddle" class="latex-formula">

Mathematics

1 answer:

MissTica2 years ago

6 0

Answer:

-3

Step-by-step explanation:

Basically it's like if you owe a dollar (-1), and then you owe 2 more dollars (-2), now you owe 3 dollars (-3).

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Can someone tell me the answer please ?<br>

monitta

Answer:

130 degrees

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

at a conference of 250 people, 30% of the participants are french, 35% are americans, 20% are germans, and the rest are of the o

Lady bird [3.3K]

Ok...we got 250 people
30% are French, 35% are Americans, 20% are Germans....thats 85%.
This means 15% are from other countries

3 not from other countries...
0.85 * 0.85 * 0.85 = 0.6

0.6(250) = 150 students <===

5 0

2 years ago

Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu

Alona [7]

Answer:

We have the equation

$c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]$

Then, the augmented matrix of the system is

$\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]$

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

$\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]$

This matrix is in echelon form. Then, now we apply backward substitution:

$8c_4=0\\c_4=0$

$4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0$

$3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0$

$c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0$

Then the system has unique solution that is $(c_1,c_2c_3,c_4)=(0,0,0,0)$ and this imply that the vectors $v_1,v_2,v_3,v_4$ are linear independent.

4 0

2 years ago

What is the missing constant term in the perfect square that starts with x^2-12x

Ipatiy [6.2K]

Essentially, we are trying to find the missing constant term of $(x - a)^2$ (remember that we are subtracting $a$ due to the negative sign in front of the second term). Let's expand this to see what we can work with: