Answer:
the law of cosines with ABC
Step-by-step explanation:
6. 7. 13
18. 10. 28
24. 17. 41
Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.
<h3>What is the equation of a circle?</h3>
The equation of a circle of center
and radius r is given by:

In this problem, the circle is centered at the origin, hence
.
The circle contains the point (-13,0), hence the radius is found as follows:



Hence the equation is:

Then, we test if point (√5, 12) is on the circle:


25 + 144 = 169
Which is an identity, hence point (√5, 12) is on the circle.
More can be learned about the equation of a circle at brainly.com/question/24307696
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Answer:
c edge
Step-by-step explanation: