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3 years ago

Can someone help me with this question?

Mathematics

1 answer:

natali 33 [55]3 years ago

4 0

I sort the data from the lowest
17.7, 18.3, 19.2, 21.1, 21.7, 23.2, 23.4, 23.7, 25.8, 26.2, 27.3, 27.4, 29.4, 29.8, 31.6, 33.5, 37.7, 38.9, 44.9

Then I classify the data to the appropriate class
1) Class 15.0-20.9
There are 3 data, those are 17.7, 18.3, and 19.2
2) Class 21.0 - 26.9
There are 7 data, those are 21.1, 21.7, 23.2, 23.4, 23.7, 25.8, 26.2
3) Class 27.0 - 32.9
There are 5 data, those are 27.3, 27.4, 29.4, 29.8, 31.6
4) Class 33.0 - 38.9
There are 3 data, those are 33.5, 37.7, 38.9
5) Class 39.0 - 44.9
There is 1 data, that is 44.9

SUMMARY
BMI Class and frequency
15.0 - 20.9  ⇒ frequency 3
21.0 - 26.9  ⇒ frequency 7
27.0 - 32.9  ⇒ frequency 5
33.0 - 38.9  ⇒ frequency 3
39.0 - 44.9  ⇒ frequency 1

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find the value of x if A, B and C are collinear points and B is between A and C. AB= 6x, BC= x-5, AC= 23

Irina18 [472]

Answer:

x=4

Step-by-step explanation:

AB + BC = AC

AB= 6x, BC= x-5, AC= 23

Substituting what we know

6x + x-5 = 23

Combine like terms

7x -5 = 23

Add 5 to each side

7x-5+5 =23+5

7x = 28

Divide each side by 7

7x/7 = 28/7

x=4

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2 years ago

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WITCHER [35]

Answer:

Rectangle, line segment, or point.

Step-by-step explanation:

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3 years ago

A laundry mat can clean five shirts in 20 minutes. What is the rate of shirts per hour?

Anna11 [10]

Answer:

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3 years ago

Please help! I don't understand how to solve this problem

Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

$S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547$

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.