Answer:
A) -3/2 and 7
Step-by-step explanation:
this equation factors to (2x+3)(x-7)
the goal is to solve for 0
if 2x+3=0 then x=-3/2
if x-7=0 then x=7
(s - 5)(2s + 7) =
= 2s² + 7s - 10s - 35 =
= <u>2</u><u>s</u><u>²</u><u> </u><u>-</u><u> </u><u>3</u><u>s</u><u> </u><u>-</u><u> </u><u>3</u><u>5</u>
So theyre trying to scare you in this question by giving you the zeros to an already existing function. Basically if x = 1, than the reverse function of this is (x-1)
using that, we can say that the zero or "root" "-2" is equal to (x+2)same with 3, we can say (x-3)= x = 3 and with five, (x-5)= x = 5
so, we have those functions, we can multiply them to eachother to work backwards.(x+2)(x-3)(x-5) =(x^2-x-9)(x-5) =x^3 - 6x^2 - 4x + 45
please ask if you have questions
Answer: A picture of the graph would help a ton but I'm pretty sure its "<"
