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marissa [1.9K]
3 years ago
5

A publisher prints 1912 copies of a book in each print run.If they print 305 runs,the manager wants to know about how many books

will be printed. What is a reasonable estimate?
Mathematics
1 answer:
sineoko [7]3 years ago
3 0

Answer:

A reasonable estimate is [tex]1,900 * 300 = 570,000[tex]

Step-by-step explanation:

This is because 1,900 is the closest multiple of 100 for 1,912, and 300 is the closest multiple of 100 for 305. And [tex]1,900 * 300[tex] is [tex]19 * 3 * 10,000[tex].

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<h2>Answer:</h2>

<em>Question 10. </em><u><em>The truck travels faster</em></u><em>.</em>

<em>Question 11. </em><u><em>The slug travels faster</em></u><em>.</em>

<h2>Step-by-step explanation:</h2>

<h2><u>Question 10.</u></h2>

<u />

<h3>1. Find the velocity of each vehicle.</h3>

Speed=\frac{distance}{time}

Speed_{Car} =\frac{200(miles)}{2(hours)}=100mi/h. \\\\ Speed_{Truck} =\frac{300(miles)}{2.5(hours)} =120mi/h.\\ \\

<h3>2. Compare the velocities.</h3>

Speed_{Car} =100mi/h < Speed_{Truck} =120mi/h.

<em>Hence, the trucks travels faster than the car.</em>

<em></em>

<u>-------------------------------------------------------------------------------------------------------</u>

<em></em>

<h2><u>Question 11.</u></h2>

<em>Apply the same method as in question 10.</em>

<h3>1. Find the velocity of each body.</h3>

<em />Speed_{snail}=\frac{20(cm)}{(3 min)} =6.67cm/min.\\ \\Speed_{slug}=\frac{15(cm)}{(2 min)} =7.5cm/min.

<h3>2. Compare the velocities.</h3>

Speed_{snail}=\frac{20(cm)}{(3 min)} =6.67cm/min < Speed_{slug}=\frac{15(cm)}{(2 min)} =7.5cm/min.

Hence, the slug travels faster.

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Its already in slope intercept form

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