Principle(P)=$1000
Rate (r)=2%=0.02
Time=t=4 years
n=no of times the interest is compounded per year=4
Amount (A)=?
Then,
A=P{(1+r/n)}^(n×t)
=1000{1+0.02/4}^(4×4)
=1000×(1.005^16)
=1000 × 1.08307115
=1083.07115
=1083.07 (approx)
Thus at the end of 4 years the amount of money will be Rs 1083.070 approximately.
Hope this helps....
Answer:
59049
Step-by-step explanation:
9×9×9×9×9
= 9⁵
<em><u>= 59049</u></em>
Answer:
slope is 10x
Y - intercept is 7
Step-by-step explanation:
Let n be the no. of sides
(n-2)*180/n=156
180n-360=156n
24n=360
n=15
so the no. of sides is 15
Answer:
Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips are white. Then,
a) Find α
α = P (reject H0 | H0 is true) = P (X ≥ 2|E)
= P (X = 2|E) + P (X = 3|E),
We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution
= (5C2 * 5C1)/10C3 + (5C3 * 5C0)/10C3
= 0.5
So, α = 0.5
b) Find β
i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)
β = P (accept H0 | E1) = P (X ≤ 1|E1)
= (6C0 * 4C3)/10C3 + (6C1 * 4C2)/10C3
= 1/3
= 0.333
So, β = 0.333
i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)
β = P (accept H0 | E2) = P (X ≤ 1|E2)
= (7C0 * 3C3)/10C3 + (7C1 * 3C2)/10C3
= 11/60
= 0.183
So, β = 0.183
