All categories

3 years ago

What is the value of y so that the ordered pair (5, y) is a solution to the equation –5x + y = –40?

1 answer:

4 0

$-5x + y = -40\\\\x=5\\\\-5(5)+y=-40\\-25+y=-40\\y-25 = -40\\y -25+ 25 = -40+25\\y = -40+25\\\\\boxed{\bf{y=-15}}$

Answer is C.

You might be interested in

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

all real numbers are solutions

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

no solution

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

The distance between 2 points is found by ________ the x terms and squaring the result, _________ the y terms and squaring the r

Elina [12.6K]

Answer: Choice A) subtracting; subtracting

The goal is to find the legs of the right triangle, so you can find the hypotenuse. The hypotenuse is the distance between the two points. See the attached image.

7 0

3 years ago

Read 2 more answers

How do I write the exponent expression below in numbers

Irina-Kira [14]

Answer:

(3^6)/2

Step-by-step explanation:

make sure everything as the numerator is in parenthesis

4 0

3 years ago

Write the following in exponential form. d · d · d · d · d · d · d · d · d

Nastasia [14]

Answer: d^9

Step-by-step explanation: i dunno it is what it is

3 0

2 years ago

Translate the phrase into an algebraic expression. w more than 9

lesantik [10]

W+9 or 9+w would be the answer

8 0

3 years ago