(1+x^2)^8
=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)
=1+8x^2+28x^4+56x^6+70x^8+....)
For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.
1.01=(1+0.1^2) => x=0.1 in the above expansion
(1.01)^8
=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]
=1+0.08+0.0028+0.000056 (+0.00000070)
=1.082856 (approximately)
I supppose the answer is F(X)=X²+4， you can use the vertex to confirm.
Answer:
A. Correct: When we plug in g(x) for the x in f(x), we get H(x).
B. Correct: When we plug in g(x) for the x in f(x), we get H(x).
C. Correct: When we plug in g(x) for the x in f(x), we get H(x).
D. Correct: When we plug in g(x) for the x in f(x), we get H(x).
Step-by-step explanation:
<em>Brainliest, please!</em>
i think its -3
hope its right and helpful
if it is then mark brainlyist
