In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AH=4 and HC=1, find BH.
1 answer:
Answer:
Length of BH is 2 units.
Step-by-step explanation:
We have, ΔABC with ∠ABC = 90° and an altitude BH.
Also, it is given that the length of sides AH is 4 units and HC is 1 units.
Since, the 'Altitude Rule' states that 'the length of the altitude is the geometric mean of the line segments it bisects'.
So, we get that,
i.e.
i.e.
i.e.
Since, the length of the side cannot be negative.
So, length of BH is 2 units.
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Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)
b) Eccentricity =5
An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:
c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.
