Answer:
x = 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
Step-by-step explanation:
<u>Step 1: Define</u>
5 - 7(2 - x) = 31 - 4(2x - 5)
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute: 5 - 14 + 7x = 31 - 8x + 20
- Subtract/Add: -9 + 7x = -8x + 51
- Add 8x on both sides: -9 + 15x = 51
- Add 9 to both sides: 15x = 60
- Divide 15 on both sides: x = 4
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: 5 - 7(2 - 4) = 31 - 4(2(4) - 5)
- (Parenthesis) Multiply: 5 - 7(2 - 4) = 31 - 4(8 - 5)
- (Parenthesis) Subtract: 5 - 7(-2) = 31 - 4(3)
- Multiply: 5 + 14 = 31 - 12
- Add/Subtract: 19 = 19
Here we see that 19 does indeed equal 19.
∴ x = 4 is the solution to the equation.
Answer:
x > 7
Step-by-step explanation:
First, you start off with :
-8x + 40 > -16
Then you subtract 40 on both sides.
You get -8x > -56.
Next, you divide -8 on both sides. Cancel out the -8/-8.
After dividing, you have x > 7
Therefore the answer is x > 7!
If you have a question comment it.
The number half way between 170,000 and 180,000 is 175,000.
The answer is d,5 as 25/20 and r can divide both sides by 5 leaving us with 5/4
<span> You have :
----------------
v0 = 35 m/s
B = angle of elevation = 30 deg
a suby = - g
v suby0 = ( v0 ) ( sin B )
v suby0 = ( 35 m/s ) ( sin 30 ) = 17.5 m/s
At maximum height :
------------------------------
v suby = vy* = 0.0
t = t*
y = ymax = y*
Basic kinematics gives :
-------------------------------------
a suby = dv suby / dt = -g ------> dt = dv suby /a suby
v suby = dy/dt ------> dt = dy / vsuby
dt = dv suby / a suby = dy / v suby
( v suby ) ( d v suby) = ( a suby ) dy = ( -g ) dy
Now integrate and get :
-----------------------------------
( v suby* )^2 - ( v suby0)^2 ( 1/2 ) = ( -g ) ( ymax )
ymax = [ ( v suby0 )^2 - ( v suby* )^2 ] / [ ( 2 ) ( g ) ]
ymax = ( 17.5 m/s )^2 - ( 0.0 m/s )^2 ] / [ ( 2 ) ( 9.807 m/s^2 ) ]
ymax = 15.6 m <------------------
Check the result:
--------------------------
t* = v suby0 / g = ( 17.5 m/s ) / ( 9.807 m/s^2 ) = 1.784 s
y* - y0 = ( v suby0 ) ( t* ) - ( g/2 ) ( t* )^2
y* = ( 17.5 m/s ) ( 1.784 s ) - ( 9.807 m/s^2 / 2 ) ( 1.784 s )^2
y* = ymax = 31.23 m - 15.61 m = 15.6 m
The ymax values agree.</span>
