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Kamila [148]
2 years ago
8

Justin likes to get 7 hours of sleep. He woke up after sleeping for 5 1/3 hour. How many more hours does he need to get the amou

nt of sleep he likes?
Mathematics
1 answer:
Valentin [98]2 years ago
8 0

Answer:

He needs 1 hour 40 minutes more to get the amount of sleep he likes or 1 2/3 hours

Step-by-step explanation:

Justin likes to get 7 hours of sleep.

He woke up after sleeping for 5 1/3 hour = 5 hours 20 mins

Number of more hours needed to get the amount of sleep he likes= 7 hours - 5 1/3 hours.

1 hour = 60 minutes

1/3 hours = 60/3 = 20 minutes

Hours         Minutes

7                     00       when we borrow 1 hour we borrow 60 minutes

<u>5                    20</u>

<u> 1                   40</u>

<u />

He needs 1 hour 40 minutes more to get the amount of sleep he likes

or 1 2/3 hours

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Write an equation to represent the following statement 29 is 6 more than K solve for K<br><br> K =
Lerok [7]

Answer:

<h2>23</h2>

Step-by-step explanation:

29 is 6 more than K

Let's create an equation

29 = 6 + k

Move variable to L.H.S and change its sign

Similarly, move constant to R.H.S and change its sign

- k = 6 - 29

Calculate

- k =  - 23

Change the sign on both sides of the equation

k = 23

Hope this helps..

Best regards!!

4 0
3 years ago
355 divided 14 hiksdjkndndf
vaieri [72.5K]

Answer:

Rounded to the nearest whole number is 25

4 0
3 years ago
A spring has a natural length of 7 m. If a 4-N force is required to keep it stretched to a length of 11 m, how much work W is re
bezimeni [28]

Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force F and the distance d  that the object moves:

W=Fd

If F is measured in newtons and d<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

W=\int\limits^b_a {f(x)} \, dx

Hooke’s Law states that the force required to maintain a spring stretched x    units beyond its natural length is proportional to

f(x)=kx

where k is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1

Thus F=x

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18

18 J is the work required to stretch a spring from 7 m to 13 m.

5 0
3 years ago
Thang decided to borrow $2000 from his local bank to help pay for a car. His loan was for 3 years at a simple intrest rat it 5%.
irakobra [83]

Answer:Thang will pay $300 as interest

Step-by-step explanation:

We would apply the formula for determining simple interest which is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

From the information given

T = 3 years

P = $2000

R = 5%

Therefore

I = (2000 × 5 × 3)/100

I = 30000/100

I = $300

3 0
3 years ago
I have no idea what the answer is or how to get it.
Lostsunrise [7]

I can't see the question

5 0
3 years ago
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