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chubhunter [2.5K]
3 years ago
13

13. On a trip of 525 miles, how many minutes faster is it to travel at 60 miles per hour than

Mathematics
1 answer:
lara [203]3 years ago
5 0
I have no clue hahaha
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Which three values are greater than
solniwko [45]

Answer:

3/4 is greater than 1/2

45% = 9/20 is less than 1/2

1/3 is less than 1/2

0.62 is greater than 1/2

59% = 59/100 is greater than 1/2

0.315 is less than 1/2

So, A, D and E are greater than 1/2

Hope this helps!

6 0
3 years ago
Jess made 3 different stacks of wooden blocks. The first stack was 8 blocks high ,the second stack was 4 blocks higher than the
kirill [66]

Answer:

Jess used 40 blocks in total.

Step-by-step explanation:

First stack: 8 blocks

Second stack: First stack + 4 = 8 + 4 = 12 blocks

Third stack: Second stack + 8 = 12 + 8 = 20 blocks

Total number of blocks: First stack + Second stack + Third stack = 8 + 12 + 20 = 40 blocks

3 0
3 years ago
What is the range of Y = l0g8X?
maw [93]

Step-by-step explanation:

all real numbers not equal to 0

all real numbers

5 0
1 year ago
Read 2 more answers
What is the exponential regression equation for the data set?
Ne4ueva [31]

Answer:

Exponential Regression. An exponential regression is the process of finding the equation of the exponential function that fits best for a set of data. As a result, we get an equation of the form y=abx where a≠0 .

Step-by-step explanation:

6 0
3 years ago
Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d
Olegator [25]

Answer:

The speed of the cars is 32 \frac{km}{h}

Step-by-step explanation:

First we must first have the clear concept that speed=\frac{distance}{time} or s=\frac{d}{t}

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: s_{1}=s+1 , t_{1}=2 and d_{1}= d_{2}

Car 1: s_{2}=s-10 , t_{2}=3 and d_{1}= d_{2}

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

d_{1}=s_{1}*t_{1}

d_{1}=(s+1)*2

d_{1}=2s+2

<em>Car 2</em>

d_{2}=s_{2}*t_{2}

d_{2}=(s-10)*3

d_{2}=3s.30

d_{1}=d_{2}

2s+2=3s-30

2+30=3s-2s

32=s

The speed of the cars is 32 km/hr

7 0
3 years ago
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