PLSSSSSSS HURRRY
2 answers:
You might be interested in
<u>Answer:</u>
<em>The value of x in log x + log 3 = log 18 is </em><em>6</em><em>.</em>
<u>Solution:</u>
From question, given that log x + log 3 = log 18 ---- eqn 1
Let us first simplify left hand side in above equation,
We know that log m + log n = log (mn) ----- eqn 2
Adding log m and log n results in the logarithm of the product of m and n (log mn)
By using eqn 2, log x + log 3 becomes log 3x.
log x + log 3 = log 3x ---- eqn 3
By substituting eqn 3 in eqn 1, we get
log 3x = log 18
Since we have log on both sides, we can cancel log and the above equation becomes,
3x = 18
Thus the value of x in log x + log3 = log18 is 6
The Riemann sum with n = 6, taking the sample points to be midpoints is - 12.0625
<h3>What is Riemann sum?</h3>
Formula for midpoints is given as;
M = ∑0^n-1f((xk + xk + 1)/2) × Δx;
From the information given, we have the following parameters
- x0 = 0
- n = 6
- xn = 3
Let' s find the parameters
Δx = (3 - 0)/6 = 0.5
xk = x0 + kΔx = 0.5k
xk+1 = x0 + (k +1)Δx
Substitute the values
= 0 + 0.5(k +1) = 0.5k - 0.5;(xk + xk+1)/2
We then have;
= (0.5k + 0.5k + 05.)/2
= 0.5k + 0.25.
Now f(x) = 2x^2 - 7
Let's find f((xk + xk+1)/2)
Substitute the value of (xk + xk+1)/2)
= f(0.5k+ 0.25)
= 2(0.5k + 0.25)2 - 7
Put values into formula for midpoint
M = ∑05[(0.5k + 0.25)2 - 7] × 0.5.
To evaluate this sum, use command SUM(SEQ) from List menu.
M = - 12.0625
A Riemann sum represents an approximation of a region's area from addition of the areas of multiple simplified slices of the region.
Thus, the Riemann sum with n = 6, taking the sample points to be midpoints is - 12.0625
Learn more about Riemann sum here:
#SPJ1
