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DIA [1.3K]
4 years ago
6

Protein folding and lipid-bilayer formation result in decreased entropy for a protein molecule and bilayer components. The decre

ase in entropy is balanced by a large increase in the entropy of the surrounding ________.
a. Temperature
b. Salt solutions
c. Pressure
d. Water molecules
Chemistry
1 answer:
creativ13 [48]4 years ago
5 0

Answer:

A decrease in entropy is balanced by a large increase in the entropy of the surrounding water molecules.

Explanation:

Water's ability to dissolve a wide variety of molecules is important, but more important is the hydrophobic effect, which drives the aggregation of hydrophobic molecules and plays a role in the folding of proteins and formation of lipid-bilayers.

Entropy is a measure of disorder of a system. Forcing water to be ordered decreases entropy, a very unfavorable situation. Water has the ability to force hydrophobic molecules away causing their aggregation. Water gains entropy when the fatty acids (hydrophobic) are forced into the lipid-bilayer.  Thus, a decrease in entropy is balanced by a large increase in the entropy of the surrounding water molecules.

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If you reacted 183 grams of copper sulfate with excess iron, what mass of copper would you expect to make? You may need to balan
Nezavi [6.7K]

The question does not provide the equation

Answer:-

72.89 grams

Explanation:-

The balanced chemical equation for this reaction is

CuSO4 + Fe --> FeSO4 + Cu

Molecular weight of CuSO4 = 63.55 x 1 + 32 x 1 + 16 x 4

= 159.55 gram

Atomic weight of Cu = 63.55 gram.

According to the balanced chemical equation

1 CuSO4 gives 1 Cu

∴159.55 gram of CuSO4 would give 63.55 gram of Cu.

183 gram of CuSO4 would give 63.55 x 183 / 159.55

= 72.89 grams of Cu

7 0
4 years ago
The same force is applied separately to two objects, A and B. B has twice the mass of A. What happens?
Alexeev081 [22]

Answer:

B's acceleration is half that of A

Explanation:

The force equation is;

Force = mass × acceleration

According to Newton's second law of motion, which explains the relationship between acceleration and mass of an object, an inverse relationship exists between the mass and the acceleration. For the same amount of force, an increase in mass (m) means a constant decrease in acceleration (a) of the object. In other words, if the mass of an object increases by two times, the acceleration will decrease by two times.

In this case involving objects A and B which has the same amount of force applied, object B has TWICE the mass of A. Using Newton's second law, this means that object B's ACCELERATION WILL BE HALF OF THAT OF OBJECT A.

5 0
3 years ago
What is an endothermic reaction?
GrogVix [38]
C is the right answer as endothermic reaction takes in the heat. That is why cooling effect is observed whenever such reaction takes place.
Hope this helped :)
3 0
3 years ago
What is the number of moles of glucose C6H12O6 in a 134g sample?
Shkiper50 [21]
The question is simply asking to convert from units of mass to units of moles. To do this, a conversion factor is needed. For this case, we use the molar mass of glucose which is equal to 180.18 g/mol. We do as follows:

134 g C6H12O6 ( 1 mol / 180.18 g ) = 0.744 mol <span>C6H12O6</span>
5 0
4 years ago
2.6(b) A sample of 2.00 mol CH3OH(g) is condensed isothermally and reversibly to liquid at 64°C. The standard enthalpy of vapori
Sophie [7]

Answer:

The value of W is 5.602 kJ, Q is -70.6 kJ, change in U is -65 kJ, and change in H is -70.3 kJ.

Explanation:

Based on the given information, the mass of CH3OH given is 64 grams, which is condensed isothermally and reversibly to liquid at 64 degrees C. The given standard enthalpy of vaporization of methanol at 64 degrees C is 35.3 kJ per mole.

The moles of CH3OH can be determined by using the formula,  

Moles = Mass / Molar mass

= 64.0 grams / 32.0 grams per mole

= 2 mol

The amount of energy given by the process of condensation is,  

ΔH = 2 mol × 35.3 kJ/mol = 70.6 kJ

In condensation heat is given off, thus, it is an exothermic process, hence, q will be -70.6 kJ

The work or W can be calculated by using the formula,  

W = -P ΔV

Let us first find the volume of 2.0 mole gas at 64 °C, or 64 + 273 = 337 K,  

PV = nRT

V = nRT/P

= 2 mol × 0.08206 L atm per mol K × 337 K/1 atm

= 55.3 L

As the liquid condenses in the process, the change in volume would be negligible. So, the volume change will be -55.3 L

W = - 1 atm × - 55.3 L

W = 55.3 L.atm

W = 55.3 L.atm × 101.3 J/1 L atm = 5602 J

W = 5602 × 1 kJ / 1000 J = 5.602 kJ

W = 5.602 kJ

Now U can be calculated using the formula,  

U = q + W

= -70.6 kJ + 5.602 kJ

= -65. kJ

Thus, q = -70.6 kJ, W = 5.602 kJ, U = -65 kJ, and ΔH = -70.3 kJ.  

4 0
3 years ago
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