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Delvig [45]
3 years ago
7

Which activity is most likely involved with the study of electrochemistry?

Chemistry
1 answer:
snow_tiger [21]3 years ago
5 0
The answer is that, from the answer choices, placing zinc and copper in an electrolyte is most likely involved with the study of electrochemistry.

Electrochemistry is the use study of the chemical reactions in relation to electric energy. It comprises the use of electric energy to produce chemical changes and the use of chemical reactions to produce electric energy.

The chemical reactions that produce or use electric energy are carried out in electrolytic cells.

Electrolytic cells consist of a pair of electrodes submerged in an electrolytic solution.


Zinc and copper are good pieces of conductors that work as electrodes in the electrolytic solution. Then, this is the correct answer..    

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Can someone answer 1-10 for me or the one you know I’ll give you brainlest!!!
Reika [66]
1. Coefficient
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3. Products
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I’m sorry if I’m wrong
5 0
3 years ago
Soda pop is carbonated with CO2. Mark puts one bottle of soda pop in the refrigerator and leaves the other out in the hot sunlig
fomenos

Answer:

The one left in the hot sunlight.

Explanation:

The solubility of gases decreases when temperature increases. The gas in the soda pop (CO2) left in the sun will not stay dissolved as much as the on left in the refrigerator.

3 0
2 years ago
What are the units of k in the following rate law?
Ludmilka [50]

Answer:

B. \frac{1}{M^{2} s }

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * M^{2} * M^{1}

k= (M/s) / (M^{3})

k= \frac{1}{M^{2} s }

You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= \frac{M^{1-n} }{s }

k= \frac{M^{1-3} }{s }= \frac{m^{-2}}{s}= \frac{1}{M^{2} s }

8 0
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How did the elements begin to stratify?
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Explanation:

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In ionic bonds, valence electrons are
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