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3 years ago

(81m^6) 1/2 (Shift +6)

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

Step-by-step explanation:

$\sqrt{81 {m}^{6} }$

= 9m³

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How modeling partialproducts can be used to find the products of greater numbers.

ratelena [41]

I'm not sure exactly what you mean, but I'm amusing what you mean. You can multiply the smaller number by a part of the bigger number. for instance, 45x5. You can multiply 5x5 and that =25, then mulitply 40x5=200. Then add 400+25=225. So, 45x5=225.

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4 years ago

What is the factors of x^2-16x+64

ddd [48]

Answer:

(x-8)² or (x-8)(x-8)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Of all college degrees awarded in the United States, 50% are bachelor's degrees, 59% are earned by women, and 29% are bachelor's

Natasha2012 [34]

Answer:

P(W|B) = 0.58

Step-by-step explanation:

The conditional probability formula tells you ...

P(W | B) = P(W&B) / P(B)

= 0.29/.050

= 0.58

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4 years ago

The number 20 is no less than the difference of 4 times a number c and 8.

sammy [17]

Answer:

20 >= 4*c - 8

Step-by-step explanation:

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3 years ago

A construction firm bids on two different contracts. Let E1 be the event that the bid on the first contract is successful, and d

NARA [144]

Answer:

(a) 0.56

(b) 0.06

Step-by-step explanation:

P(E1) = 0.7 and P(E2) = 0.8

(a) The probability that both bids are successful is given by the product of the probability of success of each bid:

$P(E1\ and\ E2) = 0.7*0.8=0.56$

(b) The probability that neither bid is successful is given by the product of the probability of failure of each bid:

$P(not\ E1\ and\ not\ E2)= (1-P(E1))*(1-P(E2))\\P(not\ E1\ and\ not\ E2)=0.3*0.2=0.06$

(c) The probability that the firm is successful in at least one of the two bids is given by the sum of the probability of success of each bid subtracted by the probability that both bids are successful:

$P(E1\ or\ E2)=P(E1)+P(E2) - P(E1\ and\ E2)\\P(E1\ or\ E2)=0.7+0.8-0.56\\P(E1\ or\ E2)=0.94$

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3 years ago