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Agata [3.3K]
3 years ago
11

Identify your unknowns and use your experimental evidence to support your identification

Chemistry
1 answer:
Masteriza [31]3 years ago
3 0
<span>During an experiment, given that other elements that make up the compound are identified, an unknown element x can easily make separate if certain properties of that unknown element is exhibited in the experiment. So, the first thing to do would be to identify the compound, identify and isolate all the knowns and one can test to see the properties which the unknown element is giving and make a reasonable deduction from that.For example if we were testing for the presence of water in Copper(II) sulfate . if water is in the sample that we were testing for, we will see that the sample will turn blue because of the presence of water</span>
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Explanation:

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3 years ago
One of relatively few reactions that takes place directly between two solids at room temperature is Ba(OH)2 · 8H2O + ammonium th
Hatshy [7]

Answer:

\boxed{\text{3.1 g}}

Explanation:

We will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:           315.46               76.12

           Ba(OH)₂·8H₂O + 2NH₄SCN ⟶ Ba(SCN)₂ + 2NH₃ + 10H₂O

m/g:             6.5

1. Moles of Ba(OH)₂·8H₂O

\text{Moles of Ba(OH)$_{2}\cdot $8H$_{2}$O}\\= \text{ 6.5 g Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}{\text{ 315.46 g Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}

2. Moles of NH₄SCN

The molar ratio is 2 mol NH₄SCN:1 mol Ba(OH)₂·8H₂O

\text{Moles of NH$_{4}$SCN} =\text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{2 mol NH$_{4}$SCN}}{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0412 mol NH$_{4}$SCN}

3. Mass of NH₄SCN

\text{Mass of NH$_{4}$SCN} = \text{0.0412 mol NH$_{4}$SCN} \times \dfrac{\text{76.12 g NH$_{4}$SCN}}{\text{1 mol NH$_{4}$SCN}} =\\\textbf{3.1 g NH$_{4}$SCN}\\\\\text{You must use }\boxed{\textbf{3.1 g}}\text{ NH$_{4}$SCN}

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4 years ago
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Answer:

Explanation:

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Hope this helps:)

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