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Vesna [10]
3 years ago
11

How many estimated stars do we have in our Milky Way galaxy

Chemistry
2 answers:
Angelina_Jolie [31]3 years ago
6 0

Answer:

Specifically 100 billion-400 billion.

densk [106]3 years ago
4 0
100 thousand million stars!!

Astronomers estimate there are about 100 thousand million stars in the Milky Way alone.

Or ?? ⬇️

100 billion - 400 billion
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Predict how the surface of a sand dune would change if a river began flowing through the area over the course of 10,000 years. W
dedylja [7]

Answer:

the sand dune would become flattened and eventually turn into sedementary rock

8 0
3 years ago
Patricia and Elliott are trying to figure out how much the temperature would have to increase from the freezing point of hydroge
Fudgin [204]

Answer:

545.7 degrees

Explanation:

Hope this helps :D

7 0
3 years ago
What is the Basis of chemistry
Kipish [7]

Answer: In chemistry, there are three definitions in common use of the word base, known as Arrhenius bases, Brønsted bases and Lewis bases. All definitions agree that bases are substances which react with acids as originally proposed by G.-F. Rouelle in the mid-18th century.

Explanation:

6 0
3 years ago
Consider an ionic compound, MX2, composed of generic metal M and generic, gaseous halogen X.
siniylev [52]

Lattice energy U(MX2) to calculate

Use Born-Haber(-Fajans) Cycle

http://en.wikipedia.org/wiki/Born%E2%80%...

M(s) + X2 → MX2(s) ΔHf°MX2 = -957 kJ mol^-1

M(s) →ΔHsub(M)→ M(g) ΔHsub = 123kJ mol^-1

M(g) →ΔHIE1(M)→ M^+ + e⁻ 757 kJ mol^-1

M^+→ΔHIE2(M)→ M^2+ + e⁻ 1451 kJ mol^-1

X2 →ΔHBE(X2)→ 2X +153 kJ mol^-1

X + e⁻→ΔHEA(X)→ X^- -313 kJ mol^-1

ΔHfo = U + ΔHsub(M) + IE1 + IE2 + ΔHdissX2 + 2EA1(X)

-957= U + 123 + 757 + 1451 + 153 – 626 = U + 1858

U = -2815 kJ mol^-1 The –ve sign is often dropped

5 0
4 years ago
The handbook density of gold is 19.3
Soloha48 [4]

Answer:

Percent error = -4.7%

Explanation:

Given data:

Actual density value = 19.3 g/cm³

Measured value of density by student = 18.4 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = ( measured value - actual value / actual value ) × 100

Now we will put the values.

Percent error = ( 18.4 g/cm³ - 19.3 g/cm³ /  19.3 g/cm³) × 100

Percent error = (-0.9 g/cm³ /  19.3 g/cm³) × 100

Percent error = -0.047  × 100

Percent error = -4.7%

Negative sign shows that measured value is less than actual value.

3 0
3 years ago
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