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1 year ago

In order to make 0.500 L of a 0.475 M solution, you will need to weigh out how many grams of sucrose (MM = 342 g/mol)?

1 answer:

4 0

The first step to solve this problem is to multiply the volume of solution times its concentration to find the number of moles needed, remember that M=mol/L:

$0.500L\cdot\frac{0.475mol}{L}=0.2375mol$

Now, use the molar mass of sucrose to find the number of grams needed to make the solution. This is, multiply the number of moles needed times the molar mass:

$0.2375mol\cdot\frac{342g}{mol}=81.225g$

It means that to make 0.500L of a 0.475M you will have to weigh 81.225g of sucrose.

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The answer will be B.

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3 years ago

Is this atom more likely to gain electrons or to lose electrons? Explain how you can tell

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Answer:

Likely to gain electrons

Explanation:

The atom shown is likely to gain additional electrons to complete its electronic configuration.

Since this is a neutral specie, the number of protons and electrons are the same.
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If the atom gains two additional electrons, the octet configuration is attained
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3 years ago

the reaction of Al with HCl to produce hydrogen gas. What is the pressure of H2 if the hydrogen gas collected occupies 14 L at 3

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Answer:

Pressure for H₂ = 11.9 atm

Option 5.

Explanation:

We determine the complete reaction:

2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)

As we do not know anything about the HCl, we assume that the limiting reactant is the Al and the acid is the excess reagent.

Ratio is 2:3.

2 moles of Al, can produce 3 moles of hydrogen

Therefore 4.5 moles of Al must produce (4.5 . 3) / 2 = 6.75 moles

Now we can apply the Ideal Gases law to find the H₂'s pressure

P . V = n . R . T → P = (n . R .T) / V

We replace data: (6.75 mol . 0.082L.atm/mol.K . 300K) / 14L

Pressure for H₂ = 11.9 atm

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2 years ago

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The nitrate anion is Select one: a. a strong acid. b. a strong base. c. amphoteric. d. a strong reducing agent. e. a strong oxid

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Answer: Option (e) is the correct answer.

Explanation:

Chemical formula of a nitrate ion is $NO^{-}_{3}$ and it acts as a strong oxidizing agent because it itself gets reduced easily.

As we know that an oxidizing agent tends to oxidize other substances by itself gaining electrons. As a result, there will occur a decrease in its oxidation state.

The oxidation number of nitrogen in $NO^{-}_{3}$ is +5. So, it gains electrons and helps in oxidizing other substances.

Thus, we can conclude that the nitrate anion is a strong oxidizing agent.

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3 years ago