Question

In order to make 0.500 L of a 0.475 M solution, you will need to weigh out how many grams of sucrose (MM = 342 g/mol)?

Answer 1

The first step to solve this problem is to multiply the volume of solution times its concentration to find the number of moles needed, remember that M=mol/L:

$0.500L\cdot\frac{0.475mol}{L}=0.2375mol$

Now, use the molar mass of sucrose to find the number of grams needed to make the solution. This is, multiply the number of moles needed times the molar mass:

$0.2375mol\cdot\frac{342g}{mol}=81.225g$

It means that to make 0.500L of a 0.475M you will have to weigh 81.225g of sucrose.