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3 years ago

13

How mant decimal points is 4.20and 0.93

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

2

Step-by-step explanation:

I had this question and it was right

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-5x-3y=22 help plz

Lerok [7]

Answer:

<h2>(-2, -4)</h2>

Step-by-step explanation:

Put the coordinates of the points to the equation, and check it:

(-4, -1) → x= -4, y = -1

L = -5(-4) - 3(-1) =20 + 3 = 23

R = 22

L ≠ R

(-1, -4) → x= -1, y = -4

L = -5(-1) - 3(-4) = 5 + 12 = 17

R = 22

L ≠ R

(-2, -4) → x= -2, y = -4

L = -5(-2) - 3(-4) = 10 + 12 = 22

R = 22

L = R CORRECT :)

(-4, -2) → x = -4, y = -2

L = -5(-4) - 3(-2) = 20 + 6 = 26

R = 22

L ≠ R

3 0

3 years ago

Find the value of x? PLEASE HELP ME (:

vova2212 [387]

The shape in the middle is a quadrilateral, so the bottom right hand corner should add up to the rest of the angles to give 360 degrees.

40 + 80 + 110 = 230°

360 - 230 = 130°

The line on which x is on is a straight line, and a straight line is 180 degrees.

Therefore x has to be 180 - 130 to make sure it adds up to give 180 degrees.

180 - 130 = 50

∴ x = 50°

7 0

3 years ago

Can someone help me solve this

Ipatiy [6.2K]

Answer:

∠ 6 = 38°

Step-by-step explanation:

∠6 and 38° are vertical and congruent, thus

∠ 6 = 38°

3 0

3 years ago

Need the answer in 20 min !! Ty

kirill115 [55]

Answer:

15

19

14

Step-by-step explanation:

6 0

3 years ago

If sin theta = 2/3 and sex theta < 0 , find cos theta and tan theta

FromTheMoon [43]

Answer:

$\displaystyle cos\theta=-\frac{\sqrt{5}}{3}$

$\displaystyle tan\theta=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

<u>Trigonometric Formulas</u>

To solve this problem, we must recall some basic relations and concepts.

The main trigonometric identity relates the sine to the cosine:

$sin^2\theta+cos^2\theta=1$

The tangent can be found by

$\displaystyle tan\theta=\frac{sin\theta}{cos\theta}$

The cosine and the secant are related by

$\displaystyle cos\theta=\frac{1}{sec\theta}$

They both have the same sign.

The sine is positive in the first and second quadrants, the cosine is positive in the first and fourth quadrants.

The sine is negative in the third and fourth quadrants, the cosine is negative in the second and third quadrants.

We are given

$\displaystyle sin\theta=\frac{2}{3}$

Find the cosine by solving

$sin^2\theta+cos^2\theta=1$

$\displaystyle \left(\frac{2}{3}\right)^2+cos^2\theta=1$

$\displaystyle cos^2\theta=1-\left(\frac{2}{3}\right)^2=1-\frac{4}{9}=\frac{5}{9}$

$\displaystyle cos\theta=\sqrt{\frac{5}{9}}=-\frac{\sqrt{5}}{3}$

$\boxed{\displaystyle cos\theta=-\frac{\sqrt{5}}{3}}$

We have placed the negative sign because we know the secant ('sex') is negative and they both have the same sign.

Now compute the tangent

$\displaystyle tan\theta=\frac{sin\theta}{cos\theta}=\frac{\frac{2}{3}}{-\frac{\sqrt{5}}{3}}=-\frac{2}{\sqrt{5}}$

Rationalizing

$\displaystyle tan\theta=-\frac{2}{\sqrt{5}}=-\frac{2\sqrt{5}}{5}$

$\boxed{\displaystyle tan\theta=-\frac{2\sqrt{5}}{5}}$

5 0

4 years ago