-x + 2y = -1....when x = 15...so we sub in 15 for x and find y
-15 + 2y = -1
2y = -1 + 15
2y = 14
y = 14/2
y = 7 <==
<h3>3
Answers: A, C, and F</h3>
All of these equations are in the form Ax+By = C
- An equation like x+y = -1 has A = 1, B = 1, C = -1
- An equation like x+4y = 0 has A = 1, B = 4, C = 0
- An equation like 8x-3y = 20 has A = 8, B = -3, C = 20
Answer:
Therefore the Distance across the Pond is

Step-by-step explanation:
Given:
Triangle are Similar
AB = 90 ft
AC = 170 ft
BD = 207 ft
DE = x
To Find:
x = ?
Solution:
In Δ ABC and Δ DBE
∠A ≅ ∠D …………..{ measure of each angle is 90° given }
∠ABC ≅ ∠DBE ……….....{Vertical Angle Theorem}
Δ ABC ~ Δ DBE ….{Angle-Angle Similarity test}
If two triangles are similar then their sides are in proportion.
Substituting the values we get

Therefore the Distance across the Pond is

Hmm... question 3
use <span>Pythagorean Theorem
aka:</span>
c^2 = a^2 + b^2
tda (treca digital academy)
lol
Answer:
12.87
Step-by-step explanation:
Since we know that line CD is a perpendicular bisector, triangle ACD is a right triangle, and thus we can apply the Pythagorean theorem to determine the length of side CD. Since the Pythagorean theorem states that a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the adjacent sides, we can plug in the values of side AD and AC.
As side CD is the bisector of side AB, sides AD and DB are both half the length of side AB, so:
AD = 11/2
AD = 5.5
We now know two values of our equation, and thus we can solve for the missing third value.
5.5^2 + b^2 = 14^2
14^2 - 5.5^2 = b^2
196 - 30.25 = b^2
165.75 = b^2

b = 12.87