Simplify the product. 3p4(4p4 + 7p3 + 4p + 1)

2 answers:

6 0

3p^4(4p^4 + 7p^3 + 4p + 1)

=(3p^4)(4p^4+7p^3+4p+1)=(3p^4)(4p^4)+(3p^4)(7p^3)+(3p^4)(4p)+(3p^4)(1)=12p^8+21p^7+12p^5+3p^4

JulsSmile [24]3 years ago

3 0

The correct answer is 12p8+21p7+12p5+3p4 is your anwser.

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The length of the shorter base in an isosceles trapezoid is 4 in, its altitude is 5 in, and the measure of one of its obtuse ang

siniylev [52]

The sum of angles in any quadrilateral, including trapezoid, is 360⁰.
Because we have an isosceles trapezoid, we have 2 angles with measure 135⁰,
and we have 2 equal acute angles with measure x⁰.
So, we can find value of acute angle,
135*2 +2x =360⁰
270+2x=360
2x=360-270
2x=90
x=45⁰

So, acute angles in trapezoid = 45⁰.
From triangle ABC,
angle ACB =90⁰
angle A=45⁰,
so angle ABC= 180-(90-45)=45⁰
Triangle ABC is isosceles triangle,so |AC| = |CB|= 5 in.

So, longer base AA' = 5+4+5= 14 in

Now, we can find area of trapezoid.
shorter base = 4 in
longer base = 14 in
altitude =h = 5 in
Area of trapezoid =(1/2)(base1+base2)*h
Area of trapezoid = (1/2)(4+14)*5= 9*5=45 in²
Answer is 45 in².