Do you have an image of the graph?
Answer: 480 mL, 600 mL
Step-by-step explanation:
Given
The concentration of the first acid is 75%
The concentration of the second acid is 30%
The final mixture has a concentration of 50%
The final volume is 1080 mL
Suppose x and y be the volume of the first and second acid

Solving the above equations we get

So, the quantity of the first acid is 480 mL and 600 mL for the second mixture.
You would use the long division technique..
Here it looks like:
<span>
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4x − 3 |</span> <span>8x^3 − 22x^2 − 4
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|</span>
|
<span> |
and like that,,,
after you do this, you will get

hope that helps
</span>
Simplify:
3x + 4[2x -3x -3 -20x] = 25x +100
3x + 4(-21x -3) = 25x + 100
3x - 84x -12 = 25x + 100
-81x -12 = 25x + 100
Add 12 and Subtract 25x from each side
-106x = 112
X = -112/106
X = -56/53
^^^^^^^^^^
Final Answer^^
let y = x^2
4y^2 -21y + 20 = 0
solve for y
then substitute back in to get x