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3 years ago

Will give brainliest to first correct answer! are these similar or not

Mathematics

2 answers:

Tatiana [17]3 years ago

8 0

Answer:

Step-by-step explanation:

(Edit: 8*2= 16, 4*2= 8 the second rectangle is multiplied by 2!)

myrzilka [38]3 years ago

7 0

Answer: Answer: A yes they are similar

Step-by-step explanation:

lmk if i got it right :)

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I need help on #2 if 1 meter is 1000 kilometers what would the answer be

anastassius [24]

120 times because 300 divided by 25

4 0

3 years ago

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Today, 6 friends went out for lunch. Their total bill was $27.60, including tax and gratuity. They decided to split the bill equ

Paladinen [302]

Step-by-step explanation:

Right, okay, so this is a bit of a weird one. Let's go step by step.

"Today, 6 friends went out for lunch." = The number 6 is gonna be in our equation somewhere.

"Their total bill was $27.60" = so is the number 27.6

"They decided to split the bill equally" = 27.6 "split equally" (aka divided by) 6 friends is 4.6

"each paid with a $10 bill" = This is where it gets a lil weird. So, if they divided the bill among them, none of their amounts are gonna be anywhere near ten dollars. This is one of those questions that wouldn't really happen in real life. People would probably use fives instead, but whatever. So a number we'll be using for something is 10.

"How much money will each person get back?" = So we have to find the amount they all paid (10) minus the amount each one had to pay (4.6).

To put it all into a full equation...

10 - ( 27.6 / 6 )

Divide.

10 - 4.6

Subtract.

5.4

Put back into money form.

$5.40

Answer:

Each person will get back $5.40.

7 0

3 years ago

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Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.