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damaskus [11]
3 years ago
8

Alan bought 20 yards of fencing. He used 5.9 yards in one garden and 10.3 in another. Write remaining as a fraction in simplest

form
Mathematics
2 answers:
Over [174]3 years ago
7 0
Its 3.8 because if you add 5.9 and 10.3 is 16.2, and if you subtract it by 20, it should equal 3.8.
expeople1 [14]3 years ago
7 0
The answer is 3.8 

[hope this helps]

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I need to make sure this is correct .. thankyou
balu736 [363]
Yes, I am pretty sure you are correct.
6 0
3 years ago
5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest
laila [671]

It's a quadratic equation in disguise. If you let y=x^{-1}, then y^2=x^{-2}, and we can rewrite the equation as

5y^2-17y+6=0

Solve for y however you like; we get y=\dfrac25 and y=3.

But we want to solve for x, so we have

y=x^{-1}=\dfrac25\implies x=\dfrac52

y=x^{-1}=3\implies x=\dfrac13

5 0
3 years ago
Dilate the point B(-4,5) by a scale factor of 3 with the center at the origin.
malfutka [58]
Answer: B (-12, 15)

Step: (3×-4) =-12
And (3×5)= 15
5 0
3 years ago
Read 2 more answers
A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

3 0
3 years ago
Solve each equation. Check your solution. <br> A) -6a=36<br> B) -9d=-72
vovikov84 [41]
A) -6a = 36

Divide both sides by -6 so that (a) is isolated.

a = -6

Check by plugging in -6 for a.

-6a=36

-6(-6)=36

36=36

So, a=-6

B) -9d=-72

Divide both sides by -9.

d = -72/-9

d = 8

Check work by plugging in 8 for d.

-9d=-72

-9(8)=-72

-72=-72

So, d=8

~Hope I helped!~
3 0
3 years ago
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