Y^2 -11y = 0
We can factor it:
y * (y -11) = 0
So y = 11, 0
Let's imagine we enclosed the entire shape in a 15 inch wide, 21 inch tall rectangle, area 315 sq inches.
From that rectangle we have to take away the 3x6 bottom left corner, and a strip 21-6=15 inches long and 3 inches wide on the right.
A = 15×21 - 3×6 - 3×15 = 315 - 63 = 252 sq in
Answer: D. 252 inches squared, last choice
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Answer:
a = 9 meters
Step-by-step explanation:
The perimeter is the sum of the side lengths:
28 m = a + 2m + a + 8m
18 m = 2a . . . . . . . . . . . . . . . . subtract 10m, collect terms
9 m = a . . . . . . . . . . . . . . . divide by 2
The value of a is 9 meters.
Answer:
I assume you mean 16^(1/3) i.e. the cube root of 16
I am also assuming you mean the real cube root because, as you may know, every non-zero real number has three cube root - one real and two complex conjugates.
Since 16 = 8 x 2 and 8 = 2³ then (2³ x 2)^1/3 = (2³)^1/3 x 2^1/3 = 2 x 2^1/3
You might check that the cube root of 16 is about 2.52 which is twice the cube root of 2
Step-by-step explanation: