Answer:
Step-by-step explanation:
<em>Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>
<em />
<em>Height of male pilot = 74.2 inches</em>
<em />
<em>We have to find the percentile</em>
<em />
<em>X = 74.2</em>
<em />
<em>Corresponding Z score = 74.2-72.6 = 1.6</em>
<em />
<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>
<em />
<em>i.e. only 5% are below him in height.</em>
<em />
<em>Thus the malepilot is in 5th percentile.</em>
6000 would be your answer
72 / 50 = 36/25
x^16 / x^36
= x^-20
simplified form is 36 / 25x^20
Answer:
its D
Step-by-step explanation:
Answer:
t (years)= (10log 20/log 1000) in base 10
Step-by-step explanation:
N = 5 × 10^0.3t
N = 100 branches
100 = 5 × 10^0.3t
100/5 = 10^0.3t
20 = 10^0.3t
Taking log of both sides
Log 20 base 10 = 0.3t
Log 20 base 10 = (3/10)t
Multiply both sides by 10
10log 20 base 10 = 3t
Recall, log 1000 base 10 = 3
10 Log 20 base 10 = (log 1000 base 10)×t
t = (10Log 20 base 10)/(log 1000 base 10)
t (years)= (10log 20/log 1000) in base 10
The number of years it will take for the tree to have 100branches is (10log 20/log 1000) in base 10