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steposvetlana [31]
3 years ago
13

Tasha can spend more than $40 on new boots. Write and graph an inequality to describe how much she can spend.

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

x> \$40

The graph in the attached figure

Step-by-step explanation:

Let

x-----> money that Tasha can spend on new boots

we know that

The inequality that represent the situation is equal to

x> \$40

The solution is the interval--------> (40,∞)

All real numbers greater than 40

In a number line the solution is the shaded area to the right of the dashed line at 40 (open circle)

see the attached figure

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sasho [114]

Answer:

x-3

Step-by-step explanation:

f(x) = 3x - 2

g(x) = 2x + 1,

(f- g)(x) =  3x - 2  - ( 2x+1)

Distribute

            = 3x -2 -2x-1

Combine like terms

             x-3

4 0
3 years ago
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telo118 [61]

Answer:

2, 3/4 and 1

Step-by-step explanation:

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3 years ago
The lowest number is 11 the range is 13 and the median is 17 what are the 3 numbers
11Alexandr11 [23.1K]

Answer:

11, 17, and 28.

Step-by-step explanation:

x, y, z\\

Lowest number is x

Median is y

Highest number is z

x=11\\y=17\\\\z-x=17\\z-11=17\\z-11+11=17+11\\z=28\\\\x=11\\y=17\\z=28\\\\11, 17, 28

3 0
3 years ago
The temperature of a mixture is decreasing by 5∘C every hour. When it was first mixed, its temperature was recorded at −20∘C.
Mandarinka [93]

Answer:

f(x)=−5x−20

Step-by-step explanation:

It's decreasing 5 degrees every hour, which is represented by -5x

You also have to take away the 20 (-20) from where it started.

So, f(x)=−5x−20

7 0
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Consider a manufacturing process called as turning (a type of machining process) that is used to manufacture cylindrical metal s
Sav [38]

Answer: 86.64%

Step-by-step explanation:

Let x be a random variable that represents the diameter of metal samples.

Given : Population mean : \mu=10

Standard deviation: s=0.50

Specified tolerance on the diameter is 0.75 mm.

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Formula to find the z-score corresponds to x: z=\dfrac{x-\mu}{s}

At x= 0.75,  z=\dfrac{9.25-10}{0.50}=-1.5

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Using standard normal table for z-value,

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6 0
3 years ago
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